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3 years ago

Smsjwjwjdjsnejdususjsskneneje

Mathematics

1 answer:

Rasek [7]3 years ago

6 0

Hellooo!smsmsmsmsmmss

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16. Which number has the greater value,<br> 7 x 10-9 or 6 x 10-4?

Murrr4er [49]

in any case, the amount of zeros is more important than the significant digits. since 7X10-9 has a smaller exponent above the 10 than 6X10-4, it is safe to say 6X10-4 is the larger number

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3 years ago

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One uranium atom has a diameter of 3.5x10^-8 centimeters. What is the sum of 10,000 uranium atoms'

Vladimir [108]

Answer:

3.5 * 10^-4 centimeters

Step-by-step explanation:

Here, we have one uranium atom having a diameter of 3.5 * 10^-8 centimeters.

We now want to find the sum of 10,000 uranium atoms diameters

Mathematically;

That would be ;

3.5 * 10^-8 * 10,000

But 10,000 = 10^4

Thus, we have

3.5 * 10^-8 * 10^4

= 3.5 * 10^-4 centimeters

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3 years ago

F(x)=2(x+2)²-1 determine the vertex (h,k)

bazaltina [42]

The vertex would be, (-2,-1)

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3 years ago

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Which function represents the graph below?

Lady_Fox [76]

C
because the units respond to the numbers

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4 years ago

[find the area please explain steps]

RSB [31]

Length of base of the top triangle = 23 inches

Length of height of the top triangle = 47 inches

Area of the top triangle :

$= \frac{1}{2} \: \times \: base \: \times \: height$

$= \frac{1}{2} \times 23 \times 47$

$= \frac{1}{2} \times 1081$

$= \frac{1081}{2}$

$= \color{hotpink} \: 540.5 \: \:sq. inches \:$

Thus, area of the top triangle = 540.5 sq.inches

Length of base of the bottom triangle = 47 inches

Length of height of the bottom triangle = 46 inches

Area of the bottom triangle :

$= \frac{1}{2} \: \times \: base \: \times height$

$= \frac{1}{2} \times 47 \times 46$

$= \frac{1}{2} \times 2162$

$= \color{hotpink}1081 \:sq. inches$

Area of the bottom triangle = 1081 sq.inches

Area of the total figure :

= Area of top triangle + Area of bottom triangle

$= 540.5 + 1081$

$= \color{hotpink}\bold{1621.5 \: \: sq.inches}$

Therefore, the area of the figure = 1621.5 sq.inches

4 0

3 years ago