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strojnjashka [21]
3 years ago
9

If a machine requires an output of 5,000 joules of work to put out 4,000joules of work, what is the machines efficieny? (Hint: t

he formula for efficiency is below):
Efficiency= Output work/
/Input work X 100%

Answers:
100%
40%
80%
60%
Mathematics
1 answer:
stira [4]3 years ago
5 0

Answer:

The  machines efficiency is 80% .

Step-by-step explanation:

Formula

Efficiency = \frac{W_{out}\times 100}{W_{in}}

Where W_{out} represented the output work .

W_{in} represented the input work .

As given

If a machine input of 5,000 joules of work to put out 4,000 joules of work .

Input work = 5000 joules

Output work = 4000 joules

Putting the values in the formula

Efficiency = \frac{4000\times 100}{5000}

Efficiency = \frac{400000}{5000}

Efficiency = 80%

Therefore the  machines efficiency is 80% .

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Answer:

Dimensions : 37.5 * 12.5

length : 37.5

width : 12.5

Step-by-step explanation:

let x = length and y = width

x = 3y based on info from problem

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100 = 2(x + y)

substitute 3y for x

100 = 2(3y + y)

100 = 2(4y)

100 = 8y

y = 12.5

x = 3(12.5) = 37.5

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3 years ago
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6 0
4 years ago
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3 years ago
For what values of x is x + 2x = 24 true?
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