Answer:
0.2
Step-by-step explanation:
It is d i would include a visual picture but i’m lazy lol
All you have to do is substitute the y value from the 1st equation into the second equation and solve...
a) y= 2-x
5x + 4y = 5
Substitute (2-x) into the second equation anywhere there is a y...
5x + 4y = 5
5x + 4(2-x) = 5
Now solve
5x + 8 - 4x = 5
5x - 4x + 8 = 5
x + 8 = 5
x = -3
Now that you have a solution for x, substitute -3 into either of the original equations anywhere there is an x then solve for y...
y = 2 - x
y = 2 - (-3)
y = 2+3 = 5
You solved for x and got -3 and solved for y and got 5, so your solution set is
(-3, 5).
Now check it by substituting both numbers into one of the original equations and you should have a true statement if it is correct...
y = 2 - x
5 = 2 - (-3)
5 = 2+3
5 = 5
True statement... it checks!
note* during the check, if the equation would have worked out to something like 2 = 5, then that is a false statement therefore the solution set would be wrong and you'd have to go back and find the mistake.
For factorisation it is necessary that you multiply the last and first values
Here we can see : we require 27a^2
SO if we multiply the answer should be 27 and if we add the answer should be 28 ....here goes !!
a^2 + 28a + 27
a^2 + 27a + 1a + 27
Here we can see : I we multiply 27 and 1 the answer will be 27a^2 but if we add 27 and 1 as shown then answer will be 28a:
a ( a + 27 ) + 1 ( a + 27 )
( a + 1 ) × (a + 27 )
HOPE IT HELPED!!
