1) True that line x = 0 is perpedicular to y = -3. Because x = 0 is parallel to the y-axis and y = -3 is parallel to the x-axis.
2) True that all the lines that are parallel to the y-axis are vertucal lines (the y-axis is vertical)
3) False that all lines perpendicular to the x-axis have a slope o 0. Their slope trends to infinity.
4) False that the equation of the line parallel to the x-axis that passes through the point (2, –6) is x = 2. The right equation is y = - 6
5) True thath the equation of the line perpendicular to the y-axis that passes through the point (–5, 1) is y = 1
Answer:
2x-6<-18
Step-by-step explanation:
Answer:
Range = (-<em>∞, 5</em>)
Step-by-step explanation:
This is the absolute value function with transformation.
The parent function is f(x) = |x|
This function has a "negative" in front, so it makes it reflect about x axis
The -4 after x makes horizontal translation of 4 units right
the +5 at the end makes the function translate 5 units UP
<em>The graph is shown in the attached picture.</em>
<em>Looking at the graph, we can clearly see the range. The range is the allowed y-values. Hence, we can see that the </em><em>range is -infinity to 5</em>
<em />
<em>answer is not properly given, so i can't choose from the options, but the answer is -∞, 5 to 5</em>
They give us the length of side of the square which is 3-7x.
To get an expression for the perimeter that is expressed as a product we have to multiply the expression 3-7x by four since every square has four sides. This will give us an expression of 4(3-7x). We than can use the distributive property to multiply everything inside the parenthesis by 4. This will give us an expression of 12-28x.
Hi i need more informacion :)01927. i tgink is octagon