We are give the equation of the perimeter of the triangle as follows:
2a + b = 15.7
where b represents the base.
Now, if we want to calculate the length of the base, all we have to do is isolate the b in one side of the equation as follows:
b = 15.7 - 2a
We know that a = 6.3 cm, therefore, the length of the base can be calculated as follows:
b = 15.7 - 2(6.3) = 3.1 cm
Answer:
(a) 3 ft, 4 ft, 5 ft
Step-by-step explanation:
The triangle inequality requires the sum of the two short sides exceed the long side.
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a) 3 ft + 4 ft = 7 ft > 5 ft . . . . . triangle is possible
b) 4 yd + 1 2/3 yd = 5 2/3 yd < 10 yd . . . . not a possible triangle
c) 3 ft + 3 ft = 6 ft < 7 ft . . . . not a possible triangle
d) 4 in + 4 in = 8 in . . . . not a possible triangle (not greater than 8 in)
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The first set of side lengths can form a triangle: 3 ft, 4 ft, 5 ft.
The question is incomplete, here is the complete question:
The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.
When will there be less than 1 g remaining?
<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.
<u>Step-by-step explanation:</u>
All radioactive decay processes follow first order reaction.
To calculate the rate constant by given half life of the reaction, we use the equation:
where,
= half life period of the reaction = 46 days
k = rate constant = ?
Putting values in above equation, we get:
The formula used to calculate the time period for a first order reaction follows:
where,
k = rate constant =
t = time period = ? days
a = initial concentration of the reactant = 12.6 g
a - x = concentration of reactant left after time 't' = 1 g
Putting values in above equation, we get:
Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.