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sasho [114]
3 years ago
14

Harry is a builder.

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
5 0

Answer:

£39.95

Step-by-step explanation:

multiply it by £7.99×5

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This isosceles triangle has two sides of equal length , a, that are longer than the length of the base , b. The perimeter of the
Sholpan [36]
We are give the equation of the perimeter of the triangle as follows:
2a + b = 15.7 
where b represents the base.

Now, if we want to calculate the length of the base, all we have to do is isolate the b in one side of the equation as follows:
b = 15.7 - 2a

We know that a = 6.3 cm, therefore, the length of the base can be calculated as follows:
b = 15.7 - 2(6.3) = 3.1 cm
4 0
4 years ago
Show a reciprocal numerical expression for each equation using multiplication, please!
iris [78.8K]
\frac{2}{3}÷ 4 = \frac{2}{3} \times  \frac{1}{4} = \frac{1}{6}

\frac{1}{8}÷ 3 = \frac{1}{8} \times \frac{1}{3} = \frac{1}{24}

\frac{3}{4}÷ 6 = \frac{3}{4} \times \frac{1}{6} = \frac{1}{8}

\frac{1}{36}÷ 2 = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12}

4 0
3 years ago
Which triangle is possible?
guajiro [1.7K]

Answer:

  (a)  3 ft, 4 ft, 5 ft

Step-by-step explanation:

The triangle inequality requires the sum of the two short sides exceed the long side.

__

a) 3 ft + 4 ft = 7 ft > 5 ft . . . . . triangle is possible

b) 4 yd + 1 2/3 yd = 5 2/3 yd < 10 yd . . . . not a possible triangle

c) 3 ft + 3 ft = 6 ft < 7 ft . . . . not a possible triangle

d) 4 in + 4 in = 8 in . . . . not a possible triangle (not greater than 8 in)

__

The first set of side lengths can form a triangle: 3 ft, 4 ft, 5 ft.

7 0
2 years ago
Which expression represents the phrase ''4 times as much as the sum of 15 and 9'' A. 4 x (15+9) B. (4 + 15) x 9 C. 4 + 15 x 9 D.
expeople1 [14]
A. 4 × (15 + 9)
Is the correct answer.
3 0
3 years ago
Read 2 more answers
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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