X-y=50 and 2x=3y
x=y+50 so 2(y+50) = 3y
2y+100=3y
y=100
x-100=50
x=150
so our numbers are 150 and 100
150-100=50 and 150 is 3*50 and 100 is 2*50 so fits all requirements!
hope this helps you! thank you!
The expression is
5x + 5y
We are to prove that it is an odd integer when x and y are integers of opposite parity
First, we can assume
x = 2a (even)
y = 2b + 1(odd)
subsituting
10(a + b) + 5
5 [(2(a + b) + 1]
The term
2(a + b) + 1 is odd and the result of an odd number multiplied by an odd number is odd
Answer:
Given:
1). divided by
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By factorising numerator by using identity,
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2). divided by
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1) use the distance formula to find that the radius (r) of the circle = 5
2) use the midpoint formula to find that the center of the circle (h,k) = (3, 0)
3) Now use the formula of a circle and input the (h,k) and r to create:
(x - 3)² + (y - 0)² = 5² → (x - 3)² + y² = 25
4) input the "x" value given in the question (x = 0) and solve for "y":
(0 - 3)² + y² = 25 → 9 + y² = 25 → y² = 16 → y = +/- 4
Since the question states that "b" must be positive, you can disregard the -4.
Answer: b = 4
Answer:
My answer would be y=2x+1
Step-by-step explanation: