Ask question

Ask question

All categories

3 years ago

8

In City A, the temperature rises 4(degrees)F from 8 A.M. To 9 A.M. Then the temperature drops 7F from 9 A.M. To 10 A.M. In City

B, the temperature drops 6F from 8 A.M. To 9 A.M. Then the temperature drops 2F from 9 A.M. To 10 A.M. Write an expression that represents the change in temperature from 8 A.M. To 10 A.M. For each city. Simplify and interpret each sum. Use pencil and paper. Which city has the greater change in temperature?

1 answer:

Alexus [3.1K]3 years ago

5 0

Answer:

City A:

$A - 3$

City B:

$B - 8$

City B has a greater change in temperature.

Step-by-step explanation:

City A:

Let the initial temperature of city A at 8 AM = $A\ ^\circ F$

Temperature change from 8 AM to 9 AM: 4 $^\circ F$ rise

Temperature at 9 AM = $(A+4)\ ^\circ F$

Temperature change from 9 AM to 10 AM: 7 $^\circ F$ drop

Temperature at 9 AM = $(A+4 -7 )\ ^\circ F = (A-3)\ ^\circ F$

Total change in temperature = $(A - 3) - A = 3\ ^\circ F$ drop

City B:

Let the initial temperature of city B at 8 AM = $B\ ^\circ F$

Temperature change from 8 AM to 9 AM: 6 $^\circ F$ drop

Temperature at 9 AM = $(B-6)\ ^\circ F$

Temperature change from 9 AM to 10 AM: 2 $^\circ F$ drop

Temperature at 9 AM = $(B-6 -2 )\ ^\circ F = (B-8)\ ^\circ F$

Total change in temperature = $(B - 8) -B = 8\ ^\circ F$ drop

Therefore, the answer is:

<em>City B</em> has a greater change in temperature.

You might be interested in

Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute

valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

= 3 - 1 = 2

d.f.D = N - k

= 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust Jet red Cloudtran

$\overline X_1 =50.5$ $\overline X_2 =50.07143$ $\overline X_3 =55.71429$

$s_1^2=19.96154$ $s_2^2=14.68681$ $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

$=\frac{51+51+...+49+49}{35}$

= 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

$=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

$=\frac{127.1143}{2}$

= 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

$=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

$=\frac{669.8571}{32}$

= 20.93304

The F-test statistics value is :

$F=\frac{s_B^2}{s_W^2}$

$=\frac{63.55714}{20.93304}$

= 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source Sum of squares d.f Mean square F

Between 127.1143 2 63.55714 3.036212

Within 669.8571 32 20.93304

Total 796.9714 34

3 0

3 years ago

Why are asymptotes important in rational function graphs

leonid [27]

Answer:

when sketching the curves of functions.

Step-by-step explanation:

There is a wide range of graph that contain asymptotes and that includes rational functions, hyperbolic functions, tangent curves, and more. Asymptotes are important guides when sketching the curves of functions. This is why it’s important that we know the properties, general forms, and graphs of each of these asymptotes.

6 0

2 years ago

If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z

vredina [299]

Hello,

Let's assume

$t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
=z^3 - \dfrac{1}{z^3} -3(z-\dfrac{1}{z})\\\\
z^3 - \dfrac{1}{z^3}=t^3+3t=3^3+9=27+9=36


$

7 0

3 years ago

Kite ABCD is similar to kite IJKL. Angle B is congruent to the measure of angle ___.

IgorC [24]

Similarity implies correspondence. Angles are listed in the order in which they are congruent to one another. A is congruent to I, B is congruent to J, C is congruent to K, D is congruent to L.

8 0

3 years ago

Read 2 more answers

Which ordered pairs are solutions to the inequality y−4x≥−5

Crank

You have to do substitution in both sides e) (-4,2)

3 0

3 years ago