Answer:
4<C
<10
Step-by-step explanation:
Theorem: Given a triangle with sides A, B and C the sum of the lengths of any two sides of a triangle must be greater than the third side:
1. A+B>C
2. B
+C
>A
3. A+C>B
Thus given two sides of A=3 and B=7 C can be:
7
−3<C
<
7+3
C range
4<C
<10
-28 / 2 could be an answer
Answer:
15 1/4 pages im thinking please correct me if im wrong
Step-by-step explanation:
Answer:
$27
Step-by-step explanation:
336/28= 12
13×2.25= 27
(b) To have no winner within the first 6 tosses means that there must be 3 tails and 3 heads tossed. So we count how many ways can that happen. The number of ways to choose 3 heads (or tails, doesn't matter) from 6 tosses is

so 20 ways winthin the 6 tosses. but the question was "how many ways among the 128 of 7 tosses" so we need to add the 7th toss by multiplying by another 2 possibilities for the outcome of the 7th toss, giving us the answer: among the 128 there are 40 games that are tied and need the 7th toss.
(c) The probability is the number of tied games (after 6 tosses) divided by the total number of possible configurations among 6 tosses:
