Answer:
1/6
Step-by-step explanation:
Given that :
Total surveyed (u) = 120
n(Cane's chicken fingers) = 50
n(Layne's chicken fingers) = 80
n(do not like either) = 10
a)
What is the probability that someone surveyed likes both Raising Cane's and Layne's chicken fingers?
n(Cane's n Layne's) = 20
u = 120
P = required outcome / total possible outcomes
P(Layne's and Cane's chicken) = [n(Cane's n Layne's)/ u]
= 20 / 120
= 1/6
Answer:
<h3>(3,1)</h3>
Step-by-step explanation:
it could be that or (6,1), (0,3),(-3,5),(-6,7)
just look at the point on the graph.
Answer: the incubation time that separates the bottom 2.5% from the rest of the incubation times is 24.96 days.
Step-by-step explanation:
Suppose the incubation times are approximately normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = incubation times.
µ = mean time
σ = standard deviation
From the information given,
µ = 23 days
σ = 1 day
The probability value for the incubation time that separates the bottom 2.5% from the rest of the incubation times would be (1 - 2.5/100) = (1 - 0.025) = 0.975
Looking at the normal distribution table, the z score corresponding to the probability value is 1.96
Therefore,
1.96 = (x - 23)/1
x = 1.96 + 23
x = 24.96
Answer:
Wheres the picture
Step-by-step explanation:
1 1/2x = 1
3/2x = 1
x = 1 * 2/3
x = 2/3 <===
