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3 years ago

If f(x) = 8x2-5, what is f(-1)

Mathematics

2 answers:

Klio2033 [76]3 years ago

5 0

Step-by-step explanation:

Remember math is a language

f(x) : A function of x where x can be any number including a number you choose

when you see f(-1), this tells you what the function is at this given x value. So you substitute - 1 wherever you see x

8(-1)2 - 5

Nikolay [14]3 years ago

4 0

Answer:3

Step-by-step explanation:

Simply plug in -1 for anywhere you see x in the equation so...

8(-1)^2-5

8(1)-5

8-5

Hope this helps

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Indentify which values are solutions of 3x - 5 ≤ -2

azamat

Answer:

x ≤ 1

Step-by-step explanation:

First, add 5 to both sides (we want to isolate x).

3x ≤ 3

Now, we divide by 3.

x ≤ 1

That's the answer! All values equal to or less than 1 are solutions of 3x - 5 ≤ -2.

Hope this helps

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3 years ago

Evaluate the expressions.

frutty [35]

Answer:

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Assuming x > 0, which of these expressions is equivalent to 11 times the square root of 245 x to the third plus 9 times the s

ehidna [41]

The answer is 104 x times the square root of 5 x

11 times the square root of 245 x to the third plus 9 times the square root of 45 x to the third is:
 $11 \sqrt{245 x^{3} } +9 \sqrt{45 x^{3} } =11 \sqrt{245} *\sqrt{ x^{3} } +9 \sqrt{45} *\sqrt{ x^{3} }= \\ \\ =11 \sqrt{5*49} * \sqrt{ x^{2} *x} +9 \sqrt{5*9} * \sqrt{ x^{2} *x}= \\ \\ =11* \sqrt{5} * \sqrt{49} * \sqrt{ x^{2}} * \sqrt{x} +9* \sqrt{5} * \sqrt{9} * \sqrt{ x^{2} }* \sqrt{x} = \\ \\ 
=11* \sqrt{5} *7*x* \sqrt{x} +9* \sqrt{5} *3*x* \sqrt{x} = \\ \\ 
=77x* \sqrt{5*x} +27x* \sqrt{5*x} = \\ \\ 
=77x \sqrt{5x} +27x \sqrt{5x} = \\ \\ 
=104x \sqrt{5x}$

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3 years ago

Read 2 more answers

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Nitella [24]

Answer:

( x − 1 ) ( x +3 )

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3 years ago

198 -176 - {48 -(24 + 8 + 4)}}

Igoryamba

Answer:

the answer is 10

Step-by-step explanation:

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3 years ago