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hoa [83]
3 years ago
7

Find the principal.

Mathematics
2 answers:
enyata [817]3 years ago
8 0

Answer:

nwbcwkcasc

Step-by-step explanation:

sdbchbsjcb

ki77a [65]3 years ago
5 0

Answer:

Principal=4700 rupees

Step-by-step explanation:

Interest for one year = 1222 ÷ 4 = 305.5 rupees.

6.5% of principal = 305.5 rupees.

6.5 over 100 X principal = 305.5 rupees.

Principal=(305.5×100/6.5) rupees.

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The lengths of the
Dmitrij [34]

Answer:

S_{\Delta ABC} = 4·S_{\Delta EDC}

Step-by-step explanation:

From the midpoint theorem, which states that the line that a line drawn such that it joins the midpoints of two sides of a triangle, is parallel to the third side of the triangle and is equal to half the length of the third side

Therefore, the lengths of the sides of ΔDEF, drawn by joining the midpoints of ΔABC is equal to half the length of and parallel to the corresponding side of ΔABC

We therefore, have that the corresponding sides of ΔABC and ΔDEF have a common ratio and a pair of sides in each triangle form same angles, therefore;

ΔDEF is similar to ΔABC by Side, Side, Side SSS similarity.

The length of the perimeter of ΔABC, S_{\Delta ABC} = 2 × The length of the perimeter of triangle ΔEDC, S_{\Delta EDC}

S_{\Delta ABC} = 2 ×  S_{\Delta EDC}

∴  S_{\Delta ABC}  ≠ 4 ×  S_{\Delta EDC}

The statement which is incorrect is therefore;

S_{\Delta ABC}  = 4 ×  S_{\Delta EDC}.

4 0
3 years ago
How can I prove that a^(m+n)=a^m*a^n
Y_Kistochka [10]
I've got it down to m+n=m*n but that doesn't seem to help.  I'm still working
7 0
3 years ago
X+y=3 and x-ý=<br>x1 simultaneous equation<br>​
pshichka [43]

Answer:

y=1, x=2

Step-by-step explanation:

x+y=3

x-y=1

Using elimination method

x-x+y--y=3-1

2y= 2

y=1

Substitute y=1 into equation 2

x-1=1

x=1+1

x=2

7 0
2 years ago
Read 2 more answers
The function f(x) = 4x + 5 has domain 0sxs 50. What is its range?<br> The range of the function is
MrMuchimi

9514 1404 393

Answer:

  range: 5 ≤ f(x) ≤ 205

Step-by-step explanation:

You can put the extreme values of x in this linear function to see its range:

  f(0) = 4·0 +5 = 5

  f(50) = 4·50 +5 = 205

The range is 5 ≤ f(x) ≤ 205.

7 0
2 years ago
where would an imaginary line need to be drawn to reflect across an axis of symmetry so that a regular pentagon can carry onto i
irina [24]

Answer:

An imaginary line would need to be drawn at any angle to the center of the side opposite the angle to  reflect across an axis of symmetry so that a regular pentagon can carry onto itself. Hope this answer helps.

5 0
2 years ago
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