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2 years ago

Scientific notation of 0.000125

Mathematics

1 answer:

tester [92]2 years ago

5 0

Answer:

1.25 × 10^-4

Step-by-step explanation:

Move the decimal until it's at 1.25. You had to go right 4 times so it's negative. If it were 12500 then you'd do it until it was 1.2500 which would be going left so it'd be a positive 4

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Write an equation for a polynomial with all the following features: The Degree is 5. The graph of the Polynomial crosses the ver

dimulka [17.4K]

Answer: f(x) = a*x^5 + b*x^3 + c*x^2 + 12.

Step-by-step explanation:

The degree is 5, so we will have a term like:

a*x^5

it crosses the vertical axis at y = 12, then we will have a constant term equal to 12.

The polynomial has 4 terms, and we already defined two, so we can invent two more, such that the exponent must be between 1 and 4

This polynomial can be something like:

f(x) = a*x^5 + b*x^3 + c*x^2 + 12.

where a, b and c are real numbers.

Has 4 terms, f(0) = 12, then it intersects the y-axis at y = 12, and the maximum exponent is 5, then the degree of f(x) is 5.

4 0

3 years ago

Two particles travel along the space curves r1(t) = t, t2, t3 r2(t) = 1 + 2t, 1 + 6t, 1 + 14t . Find the points at which their p

GuDViN [60]

Answer:

A) points at which paths intersect : (1,1,1) ; (2,4,8)

B) DNE

Step-by-step explanation:

A) To find the points in which the particle paths intersect, it is necessary to find the values of t for which the three components of both vectors are equal:

$t_1=1+2t_2\\\\t_1^2=1+6t_2\\\\t_1^3=1+14t_2$

you replace t1 from the first equation in the second equation:

$(1+2t_2)^2=1+6t_2\\\\1+4t_2+4t_2^2=1+6t_2\\\\4t_2^2-2t_2=0\\\\t_2(2t_2-1)=0\\\\t_2=0\\\\t_2=\frac{1}{2}$

Then, for t2 = 0 and t2=1/2 you obtain for t1:

$t_1=1+2(0)=1\\\\t_1=1+2(\frac{1}{2})=2$

Hence, for t1=1 and t2=0 the paths intersect. Furthermore, for t1=2 and t2=1/2 the paths also intersect.

The points at which the paths intersect are:

$r_1(1)=(1,1,1)=r_2(0)=(1,1,1)\\\\r_1(2)=(2,4,8)=r_2(\frac{1}{2})=(2,4,8)$

B) You have the following two trajectories of two independent particles:

$r_1(t)=(t,t^2,t^3)\\\\r_2(t)=(1+2t,1+6t,1+14t)$

To find the time in which the particles collide, it is necessary that both particles are in the same position on the same time. That is, each component of the vectors must coincide:

$t=1+2t\\\\t^2=1+6t\\\\t^3=1+14t$

From the first equation you have:

$t=1+2t\\\\t=-1$

This values does not have a physical meaning, then, the particle do not collide

answer: DNE

5 0

3 years ago

Number 20 ASAP ASAP THANK YOU

stira [4]

Answer:

I think its A, Because if you look at the problome A makes sense

6 0

3 years ago

Questions are on the picture, a-e.

iris [78.8K]

The equilibrium price is $1.12.
If price is $0.98, there would be scarcity of Super Widgets.
When price is $0.98, quantity demanded is y.
When price is $0.98, quantity supplied is x.
When price is $1.22, there would be a surplus of Super Widgets.

<h3>What is equilibrium? </h3>

Equilibrium price is the price at which the quantity demanded equals the quantity supplied. The equilibrium price is $1.12.

Above equilibrium price, quantity supplied would exceed quantity demanded and there would be a surplus. When price is below equilibrium price, quantity supplied would be less quantity demanded and there would be a scarcity.

To learn more about equilibrium, please check: brainly.com/question/26075805

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5 0

2 years ago

It takes 0.5 gallon of cream to make 1 pound of butter.

worty [1.4K]

Answer:

0.5 pounds of butter.

Explanation

X pounds for 0.25 gallons.

0.5 gallon of cream - 1 pound of butter

0.25 gallons of cream - X pounds of butter

Applying cross multiplication:

0.5X = 0.25

X = 0.25 over 0.5 or 0.25/0.5

X = 0.5

Therefor, you could make 0.5 pounds of butter with 0.25 gallons of cream.

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2 years ago