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sp2606 [1]
2 years ago
6

A company dyes two sizes of rugs. A small rug requires 4 hours for dyeing and a medium-size rug requires 6 hours for dyeing. The

dyers have to make at least 20 rugs, and they must do it in less than 120 hours. Let x equal small rugs and y equal medium rugs. Which of the following inequalities can be paired with x + y ≥ 20 to create a system that represents this situation?
6x + 4y 120
4x + 6y > 120
Mathematics
1 answer:
Free_Kalibri [48]2 years ago
5 0

Answer:

4x + 6y > 120

Step-by-step explanation:

i got the same question on my midterm exam.

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<u>Given</u>:

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The value of x and y can be determined using the substitution method.

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3 years ago
How many solutions are there for the system x^2+4y^2=100 and 4y-x^2=-20
never [62]
There are 5 solutions for this system.

x^2 + 4y^2 = 100  ____1
4y - x^2 = -20  ____2
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Then equation the becomes : y^2 + y -20 =0
Now factorise the equation: (y+5) (y-4) = 0
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Using the values of y to find the values of x. From equation 1:
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y = -5, x = /100 - 4(-5)^2 = /100 - 100 = 0
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3 years ago
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its the first 1. b.

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2 years ago
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