All categories

3 years ago

Pls help soon:))

Mathematics

2 answers:

andre [41]3 years ago

8 0

C 40.7% is the answer

docker41 [41]3 years ago

6 0

Answer:

26.2 is correct on PLATO

Step-by-step explanation:

You might be interested in

A paper company produces 675,000 tissues and 1,250 boxes in 5 days.

SashulF [63]

The tissue production unit rate is _675000/5=135000_ tissues per day. 

The box production unit rate is_1250/5=250_ boxes per day. 

The paper company produces_135000/250=540_ times as many tissues per day as boxes per day.

4 0

3 years ago

Farmer sells 6.2 kg of pears and apples at the farmers market 3/5 of this away is Paris, and the rest is apples. How many kilogr

Romashka [77]

Answer:

2.48 kg

Step-by-step explanation:

1 - ⅗ = ⅖

⅖ × 6.2 = 2.48

8 0

3 years ago

The base of a triangle is nine centimeters longer than the perpendicular height. If the area of the triangle is 180 square centi

Rom4ik [11]

Answer:

The base is 24 cm long.

Step-by-step explanation:

Equations

Let's call

b= base of the triangle

h=height of the triangle

The base is 9 cm longer than the height, thus:

b = h + 9

The area of the triangle is:

$\displaystyle A=\frac{bh}{2}$

$\displaystyle A=\frac{(h+9)h}{2}$

And its value is 180:

$\displaystyle \frac{(h+9)h}{2}=180$

Multiplying by 2:

$(h+9)h=360$

Operating:

$h^2+9h-360=0$

Factoring:

$(h-15)(h+24)=0$

The only valid positive solution is:

h = 15 cm

And b = h + 9 = 24

b = 24 cm

The base is 24 cm long.

7 0

3 years ago

8y^2/3 in verbal expression

padilas [110]

The product of 8 and a number, rised to the power of two-thirds

4 0

2 years ago

Gina puts $ 4500 into an account earning 7.5% interest compounded continuously. How long will it take for the amount in the acco

Elza [17]

$~~~~~~ \textit{Continuously Compounding Interest Earned Amount} \\\\ A=Pe^{rt}\qquad \begin{cases} A=\textit{accumulated amount}\dotfill & \$5150\\ P=\textit{original amount deposited}\dotfill & \$4500\\ r=rate\to 7.5\%\to \frac{7.5}{100}\dotfill &0.075\\ t=years \end{cases}$

$5150=4500e^{0.075\cdot t} \implies \cfrac{5150}{4500}=e^{0.075t}\implies \cfrac{103}{90}=e^{0.075t} \\\\\\ \log_e\left( \cfrac{103}{90} \right)=\log_e(e^{0.075t})\implies \log_e\left( \cfrac{103}{90} \right)=0.075t \\\\\\ \ln\left( \cfrac{103}{90} \right)=0.075t\implies \cfrac{\ln\left( \frac{103}{90} \right)}{0.075}=t\implies\stackrel{\textit{about 1 year and 291 days}}{ 1.8\approx t}$

4 0

1 year ago