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amid [387]
3 years ago
15

A random sample of people is chosen to participate in a survey. For the survey results to be considered valid, which must be tru

e of the random sample?
The sample must be the same size as the population.

The sample must represent the target population.

The sample must be biased.

The sample must be a group separate from the population.
ANSWER BELOW HERE
B - The sample must represent the target population.
Mathematics
2 answers:
cricket20 [7]3 years ago
7 0

Answer:

The sample must represent the target population

Step-by-step explanation:

To figure out the answer to can eliminate the answers that don't make sense.

The question is A random sample of people is chosen to participate in a survey. For the survey results to be considered valid, which must be true of the random sample?

Lets look at our answers-

A: The sample must be the same size as the population.

That does not make sense as the answer because the sample doesn't always have to be the same size as the population. So let's cross that out.

B: The sample must represent the target population.

That Makes the most sense because if you have a survey and your trying to get people opinion the sample must represent the target.

C: The sample must be biased.

This answer also makes a bit sense but not as much as B.

D: The sample must be a group separate from the population.

This is wrong because if your trying to get multiple peoples opinion you don't need a specific or separate group from the population.

So, Our answer is B: The sample must represent the target.

meriva3 years ago
3 0

Answer The sample must represent the target population.

Step-by-step explanation:

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Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-620=\dfrac{749-620}{70-30}(x-30)

y-620=\dfrac{129}{40}(x-30)

y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)

y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}

Adding 620 on both sides, we get

y=\dfrac{129}{40}x-\dfrac{387}{4}+620

y=\dfrac{129}{40}x+\dfrac{2480-387}{4}

y=\dfrac{129}{40}x+\dfrac{2093}{4}

We need to find the y-value for x=57.

y=\dfrac{129}{40}(57)+\dfrac{2093}{4}

y=183.825+523.25

y=707.075

y\approx 707.1

Therefore, the required linear equation for the given situation is y=\dfrac{129}{40}x+\dfrac{2093}{4} and the average score for persons taking a 57-hour review course is 707.1.

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