From the question, we want to find the probability of selecting a slip of paper with the letter t on it, then selecting the letter r, with replacement.

This means the probability of selecting t and r.

That is

$P(t)\times P(r)$

There are 12 letters (total outcomes). And there are 2r and 2t.

So probability becomes

$\begin{gathered} \frac{possible\text{ outcome}}{\text{total outcome }} \\ P(t)=\frac{2}{12} \\ P(r)=\frac{2}{12} \\ P(t)\times P(r)=\frac{2}{12}\times\frac{2}{12} \\ =\frac{1}{6}\times\frac{1}{6} \\ =\frac{1}{36} \end{gathered}$

Hence the answer is

$\frac{1}{36}$

7 0

1 year ago

70% of a number is 98.

Reika [66]

Let 70% of X = 98

70%.x = 98

(70/100).x = 98

0,7x = 98

x = 98/0,7

x = 140

Then, 90%x = 90%.140

= 0,9.(140)

= 126

The answer to this question is Letter D)

I hope this has helped.

7 0

3 years ago

Read 2 more answers

*when a very low mental stability and exhaustion makes you forget to put the question

Tamiku [17]

Answer:

Step-by-step explanation:

Think of 5 positive things and 9 negative things.

O O O O O

P P P P P P P P P

5 of the positive things will cancel out 5 of the negative things, leaving behind 4 negative things.

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