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Nonamiya [84]

3 years ago

class="latex-formula"> divided by 73

Mathematics

2 answers:

luda_lava [24]3 years ago

7 0

I’m not sure but I think it’s 9^20178954 1/73

Kazeer [188]3 years ago

3 0

The answer to this question is 9^276424 73/81

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Angle Z wil change because the side length is getting longer and tbe triangle would no longer fit the conditions

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3 years ago

WILL GIVE BRAINLIEST

IrinaVladis [17]

Answer:

y=1/2x-2

Step-by-step explanation:

perpendicular lines have a neg. reciprocal for the slope.

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in this equation y=-2x+1

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3 years ago

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4 years ago

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nata0808 [166]

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2 years ago

8. For many computer tablets, the owner can set a 4-digit pass code to lock the device.

Anton [14]

Answer:

a. There 5040 different pass codes if the digits cannot be repeated

b. The probability that the pass code is 1234 is ≈ 0.0002

c. The probability that two people both have a pass code of 1234 is 4× $10^{-8}$

Step-by-step explanation:

a. How many different 4-digit pass codes are possible if the digits cannot be repeated?

There are

10 possibilities for the first digit

9 possibilities for the second digit

8 possibilities for the third digit

7 possibilities for the fourth digit

Thus there are 10×9×8×7=5040 different pass codes

b. If the digits of a pass code are chosen at random and without replacement from the digits, what is the probability that the pass code is 1234

The probability that the first digit is 1 is $\frac{1}{10}$

The probability that the second digit is 2 is $\frac{1}{9}$

The probability that the second digit is 3 is $\frac{1}{8}$

The probability that the fourth digit is 4 is $\frac{1}{7}$

Thus the probability that the pass code is 1234 is $\frac{1}{10} * \frac{1}{9} *\frac{1}{8} *\frac{1}{7} =\frac{1}{5040}$ ≈ 0.0002

c. The probability that two people, who both chose a pass code by selecting digits at random and without replacement, both have a pass code of 1234?

The probability that the pass code of the one person is 1234 is 0.0002

The probability that the pass code of the other person is 1234 is 0.0002

Thus, the probability that two people have both pass code of 1234 is

0.0002×0.0002 = 4× $10^{-8}$

3 0

4 years ago