<img src="https://tex.z-dn.net/?f=9%5E%7B20178954%7D" id="TexFormula1" title="9^{20178954}" alt="9^{20178954}" align="absmiddle"

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Nonamiya [84]

2 years ago

class="latex-formula"> divided by 73

Mathematics

2 answers:

luda_lava [24]2 years ago

7 0

I’m not sure but I think it’s 9^20178954 1/73

Kazeer [188]2 years ago

3 0

The answer to this question is 9^276424 73/81

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Answer:

The minimum sample size required to create the specified confidence interval is 2229.

Step-by-step explanation:

We have that to find our $\alpha$ level, that is the subtraction of 1 by the confidence interval divided by 2. So:

$\alpha = \frac{1-0.99}{2} = 0.005$

Now, we have to find z in the Ztable as such z has a pvalue of $1-\alpha$ .

So it is z with a pvalue of $1-0.005 = 0.995$ , so $z = 2.575$

Now, find the margin of error M as such

$M = z*\frac{\sigma}{\sqrt{n}}$

In which $\sigma$ is the standard deviation of the population and n is the size of the sample.

What is the minimum sample size required to create the specified confidence interval

This is n when $M = 0.06, \sigma = 1.1$

$0.06 = 2.575*\frac{1.1}{\sqrt{n}}$

$0.06\sqrt{n} = 2.575*1.1$

$\sqrt{n} = \frac{2.575*1.1}{0.06}$

$(\sqrt{n})^{2} = (\frac{2.575*1.1}{0.06})^{2}$

$n = 2228.6$

Rounding up

The minimum sample size required to create the specified confidence interval is 2229.

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Maria is comparing the prices of two window cleaning companies. Company A charges $6 per window and an additional $12 as service

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Part A: 6w + 12 = 5w + 15

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