So in these problems, we're dealing with absolute value. Absolute value is the real amount of the number, or it's real place value without a negative sign.
Part A: if the absolute value of X was 17, then X could equal -17 or 17.
Part B: |x+9|=15. We know that 6+9=15, so X could equal -6 or 6.
Part C: |x-10| ≤ 13. We know that 23-10 is 13. So 23 would be the greatest value of X. Then, for the smallest value of X, if we insert -3 in the equation to take the place of the variable, we get |-3-10|=13. So -3 would be the smallest value of the equation. X≤ 23 and X≥-3.
Answer:
sorry about that man
Step-by-step explanation:
Did you do something to the moderator? Or was he just rude?
Answer:
113.1 unit²
Step-by-step explanation:
A cylinder is a shape with two round ends and two parallel lines connecting the round ends.
Height=9 unit, Base=4 unit
The lateral surface area of a cylinder (A) is given by the equation:
where r is the radius of the cylinder and h is the height of the cylinder.
Given that the base = 4 unit, therefore the diameter (d) = base = 4 unit. Also the height (h) = 9 unit.
Radius (r) = d/2 = 4/2 = 2 unit
Calculating the area of the cylinder is as follows
The area of the cylinder is 113.1 unit²
