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Molodets [167]
3 years ago
5

The temperature during the month of February was at most 42° Fahrenheit in Manny's town. Which number line represents the possib

le temperature readings during the month of February?

Mathematics
1 answer:
sesenic [268]3 years ago
6 0
The correct answer is:   [A]:  "the number line in the upper, left-hand corner" .
___________________________________________________________
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HELPP
Harrizon [31]

Answer:

Step-by-step explanation:

Alright, lets get started.

Lets find slope for both bikes one by one

For bike 1 :

There are two points on the graph of Bike 1, these two points are (2,3) and (4,6)

So the slope for bike 1 is : \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

So the slope for bike 1 is : \frac{6-3}{4-2}

So the slope for bike 1 is : \frac{3}{2}

For bike 2 :

There are two points on the graph of Bike 2, these two points are (4,5) and (8,10)

So the slope for bike 2 is : \frac{y_{2}-y_{1} }{x_{2}-x_{1} }

So the slope for bike 2 is : \frac{10-5}{8-4}=\frac{5}{4}

Hence Bike 1 will win the race as slope of line bike1 is greater than slope of line bike 2.  So, answer is option D


3 0
3 years ago
Read 2 more answers
Find the missing length indicated
miskamm [114]
Check the picture below.

5 0
3 years ago
Given that the expression x³_ ax² + bx+c leaves the same remainder when divided by x + 1 or x-2, find 'a' in terms of 'b'.​
goblinko [34]

Answer:

Hi,

a=b+3

Step-by-step explanation:

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=-1&&-1&a+1&-a-b-1\\---&---&---&---&---\\&1&-a-1&a+b+1&c-a-b-1\\\end{array}

\begin{array}{c||c|c|c|c}&x^3&x^2&x&1\\---&---&---&---&---\\&1&-a&b&c\\x=2&&2&4-2a&2b+8-4a\\---&---&---&---&---\\&1&2-a&b+4-2a&c+2b+8-4a\\\end{array}

Thus:

c+2b+8-4a=c-a-b-1

3b-3a=-9

<u>a=b+3</u>

5 0
2 years ago
Complete the table. Thanks in advance
marta [7]

Answer:

20%

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Help me out with number 8!!! I’m confused and I need this by tomorrow HELP PLEASE
ivann1987 [24]
We can use elimination for these set of systems.
First, we need to set up our variables.
Belts=b
Hats=h
Now, the situation is 6 belts and 8 hats for $140. The situation after is 9 belts and 6 hats for $132.
Let’s set up our system of equations.
6b+8h=140
9b+6h=132
We need to eliminate a variable. Since b has coefficients of 6 and 9, we can easily eliminate b by multiplying the top equation by 3 and the bottom by -2.
18b+24h=420
-18b-12h=-264
Now let’s add.
12h=156
Let’s divide to get h by itself.
156/12=13=h
So a hat costs $13. We need to put in 13 for one of the equations so we can find the cost of a belt.
9b+6(13)=132
9b+78=132
We need b by itself.
9b=54
54/9=6
Belts are $6
We can also use the first equation to check our answers.
6(6)+8(13)
36+104
140.
So, the price of a belt is $6 while the price of a hat is $13.
































3 0
3 years ago
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