MIDDLE SCHOOL MATH- 4 QUESTIONS

Mathematics

1 answer:

Contact [7]2 years ago

6 0

Answer:

( I am assuming that these are all fractions)

1. 14 $\frac{4}{7}$

2. 8

3. $\frac{4}{15}$

4. 5 $\frac{8}{11}$

Step-by-step explanation:

1. First you have to convert 15 into a fraction but it must have the same denominator causing the equation to look like 105/7 - 3/7= 102/7. But you cannot just leave the fraction like that it must be simplified 14 $\frac{4}{7}$

2. Three-fifths of an hour is 36 minutes. You would next multiply 5 by 60 which would the hours into minutes 5 x 60 = 300. You would then divide 300 by 36 which would give you 8.3333333333, which I just simplified it to 8

3. In order for you to multiply a fraction you would first multiply the top then the bottom. 12 x 6= 72, 15 x 18= 270. The fraction would look like 72/270 which is simplified to $\frac{4}{15}$ .

4. First I changed the fractions into improper fractions causing the fraction to look like 36/8 x 14/11 (I got these answers by 8 by 4 then adding 4, then for the next fraction I multiplied 11 by 1 then added 3.) 36 x 14= 1224, 11 x 8= 88 the fraction would look like 1,224/88 you would simplify to 5 $\frac{8}{11}$

Hope this helps

Please tell me if I made any mistakes I enjoy learning from them.

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S=a1/1-r

valentinak56 [21]

Answer:

Step-by-step explanation:

This is an infinite geometric series. This has a sum of $\frac{a}{1-r}$

Where

a is the first term, and

r is the common ratio (one term divided by the previous term)

Let's figure out the first 2 terms by plugging in n = 1 first and then n = 2 for the series.

First term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{1-1}\\=3(\frac{1}{4})^0\\=3(1)\\=3$

Second term:

$3(\frac{1}{4})^{n-1}\\=3(\frac{1}{4})^{2-1}\\=3(\frac{1}{4})^1\\=3(\frac{1}{4})\\=\frac{3}{4}$

Let's see the common ratio: $\frac{\frac{3}{4}}{3}\\=\frac{3}{4}*\frac{1}{3}\\=\frac{1}{4}$

Thus we have a = 3 and r = 1/4. Plugging into the formula of the infinite sum, we get:

$s=\frac{a}{1-4}=\frac{3}{1-\frac{1}{4}}=\frac{3}{\frac{3}{4}}=3*\frac{4}{3}=4$

So, the answer is 4

4 0

3 years ago

Find the perimeter of a quadrilateral with vertices at R (-2, 1), S (-5, 5), T (2, 5), U (5, 1). Round your answer to the neares

Nezavi [6.7K]

Check the picture below.

now, you can pretty much count the units off the grid for the segments ST and RU, so each is 7 units long, and are parallel, meaning that the other two segments are also parallel, and therefore the same length each.

so we can just find the length for hmmmm say SR, since SR = TU, TU is the same length,

$\bf ~~~~~~~~~~~~\textit{distance between 2 points}
\\\\
S(\stackrel{x_1}{-2}~,~\stackrel{y_1}{1})\qquad 
R(\stackrel{x_2}{-5}~,~\stackrel{y_2}{5})\qquad \qquad 
% distance value
d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}
\\\\\\
SR=\sqrt{[-5-(-2)]^2+[5-1]^2}\implies SR=\sqrt{(-5+2)^2+(5-1)^2}
\\\\\\
SR=\sqrt{(-3)^2+4^2}\implies SR=\sqrt{25}\implies SR=5$

sum all segments up, and that's perimeter.