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Olin [163]
4 years ago
11

A telephone pole casts a shadow that is 37m long what is the height of the telephone pole if a statue that is 33cm fall casts a

shadow 83cm long
Mathematics
1 answer:
liberstina [14]4 years ago
3 0
Well in order to answer this we need to write out the proportions. So the pole is X meters tall but casts a shadow 37 meters long while the statue is 33 cm tall and casts a shadow 83 cm long. So we now proportionate the two heights and the two shadows and we get \frac{x}{33}= \frac{37}{83}. Then we cross multiply and get 83x= 1221and then simplify by dividing 83 from both sides and get x ≈ 14.71m.
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Answer:

There are 13 quarters, 67 nickels, and 22 dimes.


Step-by-step explanation:

The value of a quarter is $0.25, the value of dime is $0.10, and the value of a nickel is $0.05. Let there be q quarters, n nickels, and d dimes.

Let's write equations from the statements given:


<u>"Ginny's piggybank contained $8.80 in quarters, dimes, and nickels.":</u>

0.25q+0.1d+0.05n=8.80

<u>"there were two more than five times as many nickels as quarters":</u>

5q+2=n

<u>"4 less than twice as many dimes as quarters":</u>

<u>2q-4=d</u>


Plugging in equation 2 and 3 into equation 1, we can solve for q:

0.25q+0.1(2q-4)+0.05(5q+2)=8.80\\0.25q+0.2q-0.4+0.25q+0.1=8.80\\0.7q=8.80+0.4-0.1\\0.7q=9.1\\q=\frac{9.1}{0.7}=13

<em>Substituting q = 13 into equation 2 will give us nickels:</em>

n=5q+2\\n=5(13)+2\\n=67

<em>Substituting q = 13 into equation 3 will give us dimes:</em>

d=2q-4\\d=2(13)-4\\d=22


There are 13 quarters, 67 nickels, and 22 dimes.

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