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2 years ago

10

PLease help meeeeeeeeeeeeee

2 answers:

lys-0071 [83]2 years ago

8 0

Answer:The first one is a line segment the second one is a ray and the 3rd one is a line

Step-by-step explanation:

Zigmanuir [339]2 years ago

5 0

The fist one is a line segment. You would write it as AB and choose the option that does not have any arrows.

The second one is a ray. You would write it as DC and choose the option that has one arrow.

The third one is a line. You would write it as FE and choose the option that has arrows on both sides.

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Your bank account balance is −$52.85. You deposit $65.50. What is your new balance?

Doss [256]

Answer:

$12.65

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

mr. devito was ordering pencils for apl fourth grade students. There are 118 fourth graders. Pencils come in packs of 6. He need

sweet [91]

Answer:

Mr. devito needs to buy 40 packs

Step-by-step explanation:

Given:

Total number of fourth grade students = 118

The number of pencils in one pack = 6

The number pencil each student gets =2

To find:

The number of packs of pencils that is to be bought = ?

Solution:

To give all the 118 fourth grade students each 2 pencils , the total number of pencils needed will be

= > $118 \times 2$

=> 236 Pencils

We know that a pack contains 6 pencils, so the number of pack that has to be bought , in order to have 236 pencils will be

=> $\frac{ \text{total number of pencils}}{\text{ number of pencils per pack }}$

On substituting the values

=> $\frac{236}{6}$

=> 39.33

=> 40

3 0

3 years ago

Jefferson High School has a student body of 6⁴ students. Each class has approximately 6² students. How many classes does the sch

daser333 [38]

36, because 6^4 /6^2 is 6^2 and 6*6 (6^2) is 36

7 0

3 years ago

Define zero slope of line in a graph

Alex Ar [27]

It would be a straight line

7 0

3 years ago

Solve the equation for all real values of x.<br> cosxtanx - 2 cos x=-1

IceJOKER [234]

Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

<u>Step-by-step explanation:</u>

Here we have , $cosxtanx - 2 cos^2 x=-1$ . Let's solve :

⇒ $cosxtanx - 2 cos^2 x=-1$

⇒ $cosx(\frac{sinx}{cosx}) - 2 cos^2 x=-1$

⇒ $sinx = 2 cos^2 x-1$

⇒ $sinx = 2 (1-sin^2x)-1$

⇒ $sinx = 1-2sin^2x$

⇒ $2sin^2x+sinx-1=0$

By quadratic formula :

⇒ $sinx = \frac{-b \pm \sqrt{b^2-4ac} }{2a}$

⇒ $sinx = \frac{-1 \pm \sqrt{1^2-4(2)(-1)} }{2(2)}$

⇒ $sinx = \frac{-1 \pm3}{4}$

⇒ $sinx = \frac{1}{2} , sinx =-1$

⇒ $sinx = sin\frac{\pi}{6} , sinx = sin\frac{3\pi}{2}$

⇒ $x=\frac{\pi}{6} , x=\frac{3\pi}{2}$

But at $x=\frac{3\pi}{2}$ we have equation undefined as $cos\frac{3\pi}{2}=0$ . Hence only solution is :

⇒ $x=\frac{\pi}{6}$

Since , $sin(\pi -x)=sinx$

⇒ $x=\pi -\frac{\pi}{6} = \frac{5\pi}{6}$

Now , General Solution is given by :

⇒ $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$

Therefore , Solution to equation $cosxtanx - 2 cos^2 x=-1$ for all real values of x is $x=2k\pi + \frac{\pi}{6} , x=2k\pi + \frac{5\pi}{6}$ .

3 0

3 years ago