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NARA [144]
2 years ago
14

Which angle is larger?​

Mathematics
1 answer:
Tamiku [17]2 years ago
6 0
Yes I agree with the person that put that answer
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Y is inversely proportional to (x+2)² when x=1, y=2
REY [17]

Answer:

y = 18 / (x + 2)²

Step-by-step explanation:

Inversely proportional

y * (x + 2)² = k

when x=1, y=2

k = 2 * (1 + 2)²

k = 18

-----------------------

y * (x + 2)² = 18

Divide both sides by (x + 2)²

y = 18 / (x + 2)²

6 0
3 years ago
I like Memes. Do you like memes too?
enyata [817]

Answer:

Memes are amazing.

Step-by-step explanation:

They're also how I get my news.

4 0
3 years ago
Read 2 more answers
Claire received 3/8 of her allowance on Monday. What decimal shows the part of her allowance that she received?
lakkis [162]

Answer:

0.375

Step-by-step explanation:

3/8 = 0.375

4 0
2 years ago
What is (5x-2)(4x^2 -3x-2)
Ronch [10]
Answer: 20x^3 - 23x^2 - 4x + 4

Explanation:

Use distributive property:

(5x-2)(4x^2 - 3x-2)
= 20x^3 - 15x^2 - 10x - 8x^2 + 6x + 4
= 20x^3 - 23x^2 - 4x + 4
8 0
2 years ago
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State one form of the Law of Cosines and provide a trick for writing the other two forms and explain when Law of Cosines should
Yuki888 [10]

Solving for <em>Angles</em>

\displaystyle \frac{a^2 + b^2 - c^2}{2ab} = cos∠C \\ \frac{a^2 - b^2 + c^2}{2ac} = cos∠B \\ \frac{-a^2 + b^2 + c^2}{2bc} = cos∠A

* Do not forget to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

Solving for <em>Edges</em>

\displaystyle b^2 + a^2 - 2ba\:cos∠C = c^2 \\ c^2 + a^2 - 2ca\:cos∠B = b^2 \\ c^2 + b^2 - 2cb\:cos∠A = a^2

You would use this law under <em>two</em> conditions:

  • One angle and two edges defined, while trying to solve for the <em>third edge</em>
  • ALL three edges defined

* Just make sure to use the <em>inverse</em> function towards the end, or elce you will throw your answer off!

_____________________________________________

Now, JUST IN CASE, you would use the Law of Sines under <em>three</em> conditions:

  • Two angles and one edge defined, while trying to solve for the <em>second edge</em>
  • One angle and two edges defined, while trying to solve for the <em>second angle</em>
  • ALL three angles defined [<em>of which does not occur very often, but it all refers back to the first bullet</em>]

* I HIGHLY suggest you keep note of all of this significant information. You will need it going into the future.

I am delighted to assist you at any time.

7 0
2 years ago
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