Answer:
6x + 4y ≤ 50
x + y ≥ 10
Step-by-step explanation:
$6 is the cost of stuffed animals $4 is the cost of toy trucks and the her maximum budget is $50 it would be 6x+4y is less then or equal to 50 and there is AT LEAST 10 people so the amounts which are x and y would be equal to or greater than 10.
Answer:
x = - 
, x = 
Step-by-step explanation:
The absolute value function always gives a positive value, however, the expression inside can be positive or negative, that is
- 3x + 16 = 18 or -(- 3x + 16) = 18
Solving
- 3x + 16 = 18 ( subtract 16 from both sides )
- 3x = 2 ( divide both sides by - 3 )
x = -
or
-(- 3x + 16) = 18
3x - 16 = 18 ( add 16 to both sides )
3x = 34 ( divide both sides by 3 )
x = 
As a check
Substitute these values into the left side of the equation and if equal to the right side then they are the solutions.
| - 3(- ) + 16 | = | 2 + 16 | = | 18 | = 18 ← True
| - 3( ) + 16 | = | - 34 + 16 | = | - 18 | = 18 ← True
Thus x = - and x = are the solutions
54c^3d^4 + 9c^4d^2
9c^3d^2(6d^2 + c)
Answer:
50 increased by 30% is 65
Step-by-step explanation:
'Percent (%)' means 'out of one hundred':
p% = p 'out of one hundred',
p% is read p 'percent',
p% = p/100 = p ÷ 100.
30% = 30/100 = 30 ÷ 100 = 0.3.
100% = 100/100 = 100 ÷ 100 = 1.
Percentage increase = 30% × 50
New value = 50 + Percentage increase
Calculate
New value =
50 + Percentage increase =
50 + (30% × 50) =
50 + 30% × 50 =
(1 + 30%) × 50 =
(100% + 30%) × 50 =
130% × 50 =
130 ÷ 100 × 50 =
130 × 50 ÷ 100 =
6,500 ÷ 100 =
65
Or just find 30% of 50 (15) and add that
Answer:
Pretend that x and y represents the 2 numbers that we need to find.
According to the information, we know that:
x + y = 21
6x = y
Replace y in the first equation with 6x (because they are equal to each other according to the second equation):
x + y = 21
x + 6x = 21
7x = 21
x = 21/7 = 3
Now have two ways to find y, both will give us the same result:
3 + y = 21 ⇔ y = 21 - 3 = 18
6 · 3 = y ⇔ y = 18
So the numbers that we need to find are 3 and 18.
