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3 years ago

Which statement is true about 7/10 and 2/6?

Mathematics

1 answer:

77julia77 [94]3 years ago

5 0

Answer: The third answer

Step-by-step explanation:

7/10 is 0.7 and 2/6 is 0.33, 2/6 would be less than 1/2 because 1/2 is 0.5, 0.7 is greater than that benchmark

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Yo! Solving linear equations with integers! These are just some practice exercises I need help with! So they should probably be

drek231 [11]

Answer:

Step-by-step explanation:

<h3>Solving linear equation with one variable:</h3>

1) -4 + 3x = 4x - 8

Add 4 to both sides

-4 + 3x + 4 = 4x - 8 + 4

3x = 4x - 4

Subtract 4x from both sides,

3x - 4x = -4x + 4x - 4

-x = -4

$\sf \boxed{\bf x = 4}$

2) -5x - 8 = 2

Add 8 to both sides

-5x - 8 + 8 = 2 + 8

-5x = 10

Divide both sides by (-5)

$\sf \dfrac{-5}{-5}x =\dfrac{10}{-5}$

$\sf \boxed{\bf x = -2}$

3) 12r - 14 = 5(2-r)

12r - 14 = 5*2 - 5*r

12r - 14 = 10 - 5r

Add 14 to both sides

12r - 14 + 14 = 10 - 5r + 14

12r = 24 - 5r

Add 5r to both sides

12r + 5r = 24

17r = 24

Divide both sides by 17

r = 24/17

4) 3x - 8 = -(17 + 2x)

3x - 8 = -17 - 2x

Add 8 to both sides

3x - 8 + 8 = -17 - 2x + 8

3x = -9 - 2x

Add 2x to both sides

3x + 2x = -9

5x = -9

Divide both sides by 5

$\sf \dfrac{5}{5}x=\dfrac{-9}{5}\\\\\boxed{x = \dfrac{-9}{5}}$

3 0

2 years ago

Read 2 more answers

A line drawn between the two pupils of the eyes defines which of the positioning lines?

user100 [1]

Answer:

your a very beautiful dumb.asss

Step-by-step explanation:

go give your self a bj

4 0

3 years ago

Read 2 more answers

A wire b units long is cut into two pieces. One piece is bent into an equilateral triangle and the other is bent into a circle.

mezya [45]

1. Divide wire b in parts x and b-x.

2. Bend the b-x piece to form a triangle with side (b-x)/3

There are many ways to find the area of the equilateral triangle. One is by the formula A= $\frac{1}{2}sin60^{o}side*side= \frac{1}{2} \frac{ \sqrt{3} }{2} (\frac{b-x}{3}) ^{2}= \frac{ \sqrt{3} }{36}(b-x)^{2}$
A= $\frac{ \sqrt{3} }{36}(b-x)^{2}=\frac{ \sqrt{3} }{36}( b^{2}-2bx+ x^{2} )=\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}$

Another way is apply the formula A=1/2*base*altitude,
where the altitude can be found by applying the pythagorean theorem on the triangle with hypothenuse (b-x)/3 and side (b-x)/6

3. Let x be the circumference of the circle.

$2 \pi r=x$

so $r= \frac{x}{2 \pi }$

Area of circle = $\pi r^{2}= \pi ( \frac{x}{2 \pi } )^{2} = \frac{ \pi }{ 4 \pi ^{2} }* x^{2} = \frac{1}{4 \pi } x^{2}$

4. Let f(x)= $\frac{ \sqrt{3} }{36}b^{2}-\frac{ \sqrt{3} }{18}bx+ \frac{ \sqrt{3} }{36}x^{2}+\frac{1}{4 \pi } x^{2}$

be the function of the sum of the areas of the triangle and circle.

5. f(x) is a minimum means f'(x)=0

f'(x)= $\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x$ =0

$\frac{ -\sqrt{3} }{18}b+ \frac{ \sqrt{3} }{18}x+\frac{1}{2 \pi } x=0$

$(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) x=\frac{ \sqrt{3} }{18}b$

$x= \frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

6. So one part is $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$ and the other part is b- $\frac{\frac{ \sqrt{3} }{18}b}{(\frac{ \sqrt{3} }{18}+\frac{1}{2 \pi }) }$

4 0

3 years ago

Read 2 more answers

If z=sprt5 -sprt2, then Izl=

ASHA 777 [7]

Answer:

is the answer

because sprt - sprt = 0

then 5-2=3

3 0

3 years ago

For the following system, use the second equation to make a substitution for y in the first equation.

Anuta_ua [19.1K]

Answer:

2x+3x+4=6

Step-by-step explanation:

You'd plug in the y-equation which is y=3x+4 into the placement of the y in the first equation 2x+y=6,

Which would then result in 2x+3x+4=6, which is the answer

8 0

3 years ago