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den301095 [7]
3 years ago
5

Look at the screenshot please for question! Answer choices: 18 20 21 25

Mathematics
1 answer:
katen-ka-za [31]3 years ago
5 0

Answer:

The Answer is 18 then 25 then 21 then 20

Step-by-step explanation:

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Convert 25 1/3% to decimal. Round to the nearest thousandth if necessary.
Anni [7]
Decimal: 25.3333, but converted properly it is
.253333....(repeating) so to the nearest thousands it would be .253
6 0
3 years ago
Solving systems of linear inequalities
PIT_PIT [208]

Answer:

YES. (2, 7) is a solution of the system.

Step-by-step explanation:

System of linear inequalities has been given as,

y ≥ -x + 1 --------(1)

y < 4x + 2 ------(2)

If (2, 7) is a solution of the given system of inequalities, it will satisfy both the inequalities.

By substituting the coordinates of point (2, 7) in inequality (1),

7 ≥ -2 + 1

7 ≥ -1

True.

By substituting the coordinates of point (2, 7) in inequality (2),

7 < 4(2) + 1

7 < 9

True.

Therefore, point (2, 7) lie in the solution area of system of inequalities.

YES. (2, 7) is a solution of the system.

4 0
3 years ago
Assume that the terminal side of thetaθ passes through the point (negative 12 comma 5 )(−12,5) and find the values of trigonomet
zmey [24]

Answer:

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

Step-by-step explanation:

Assume that the terminal side of thetaθ passes through the point (−12,5).

In ordered pair (-12,5), x-intercept is negative and y-intercept is positive. It means the point lies in 2nd quadrant.

Using Pythagoras theorem:

hypotenuse^2=perpendicular^2+base^2

hypotenuse^2=(5)^2+(12)^2

hypotenuse^2=25+144

hypotenuse^2=169

Taking square root on both sides.

hypotenuse=13

In a right angled triangle

\sin \theta = \dfrac{opposite}{hypotenuse}

\sin \theta = \dfrac{5}{13}

\sec \theta = \dfrac{hypotenuse}{adjacent}

\sec \theta = \dfrac{13}{12}

In second quadrant only sine and cosecant are positive.

\sin \theta = \dfrac{5}{13} and \sec \theta = -\dfrac{13}{12}

6 0
4 years ago
Solve the compound inequality. 6 – x &gt; 15 or 2x – 9 ≥ 3 A. x &gt; 9 or x ≤ 6 B. x &lt; 9 or x ≥ –6 C. x &gt; –9 or x ≤ –6 D.
Vesnalui [34]

Answer:

Step-by-step explanation:

Solve the compound inequality. 6 – x > 15 or 2x – 9 ≥ 3 A. x > 9 or x ≤ 6 B. x < 9 or x ≥ –6 C. x > –9 or x ≤ –6 D. x < –9 or x ≥ 6

4 0
3 years ago
The enrollment at East Valley High School over a six-year period is displayed in the scatterplot.
garik1379 [7]
D 100% corect took my test $$$$$$$$$$$$$$
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