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3 years ago

Find the value of x. Explain your work please.Concurrency of Angle Bisectors

Mathematics

1 answer:

vovangra [49]3 years ago

5 0

Answer:

$x+5=2x-1$

combine terms

subtract x from both sides and add 1 to both sides

$6=x$

Answer is A

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6+2(7×-3) Simplify the expression

almond37 [142]

Answer:

=36

Step-by-step explanation:

$6+2(7*(-3) )\\\\=6+2(-21)\\\\=6-42\\\\=2+4-42\\\\=4-40\\\\=36$

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3 years ago

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laila [671]

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3 years ago

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Bumek [7]

Answer:

6+7=13

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Jesus spent 1/4 of his money on a pizza and 1/4 of his money on salad. What fraction of his money did Jesus spend on dinner?

katrin [286]

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2/4 of his money was spent on dinner

Step-by-step explanation:

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3 years ago

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If f(x-3)=x^2-4x+5, what's f(1-x)

olganol [36]

Answer:

$\large\boxed{f(1-x)=x^2-4x+5}$

Step-by-step explanation:

$f(x-3)=x^2-4x+5\\\\f((x-3)+3)\to\text{put x + 3 to the equation of the function:}\\\\f(x-3+3)=(x+3)^2-4(x+3)+5\\\text{use the distributive property and}\ (a+b)^2=a^2+2ab+b^2\\f(x)=x^2+2(x)(3)+3^2+(-4)(x)+(-4)(3)+5\\f(x)=x^2+6x+9-4x-12+5\qquad\text{combine like terms}\\f(x)=x^2+(6x-4x)+(9-12+5)\\f(x)=x^2+2x+2\\\\f(1-x)\to\text{put 1 - x to the equation of the funtion f(x):}\\\\f(1-x)=(1-x)^2+2(1-x)+2\\\text{use the distributive property and}\ (a-b)^2=a^2-2ab+b^2$

$f(1-x)=1^2-2(1)(x)+x^2+(2)(1)+(2)(-x)+2\\f(1-x)=1-2x+x^2+2-2x+2\qquad\text{combine like terms}\\f(1-x)=x^2+(-2x-2x)+(1+2+2)\\f(1-x)=x^2-4x+5$

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3 years ago