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Vedmedyk [2.9K]
3 years ago
7

Please help i need this done soon!

Mathematics
1 answer:
Kamila [148]3 years ago
6 0

Answer:

this is my old account and these still dont have answers

Step-by-step explanation:

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We'll assume this is an arbitrary triangle ABC.


A) No, the sines of two different angles can be whatever they want


B) sin(B)=cos(90-B)


Yes, that's always true. The "co" in cosine means "complementary" as in the complementary angle, which adds to 90. So the sine of an angle is the cosine of the complementary angle.


C) No, the correct identity is sin(180-B)=sin B. Supplementary angles share the same sine.


D) Just like A, different triangle angles often have different cosines.


Answer: Choice B



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3 years ago
Help me solve this algebra 1 question please
s344n2d4d5 [400]
You should know that simply your answer
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3 years ago
Which statement about the simplified binomial expansion of (a + b)", where n is a positive integer, is true?
Alja [10]

Answer:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

Step-by-step explanation:

The Given question is INCOMPLETE as the statements are not provided.

Now, let us try and solve the given expression here:

The given expression is: (a +b)^n, n > 0

Now, the BINOMIAL EXPANSION is the expansion which  describes the algebraic expansion of powers of a binomial.

Here, (a+b)^n  = \sum_{k=0}^{n}{n \choose k}a^{(n-k)}b^{(k)}

or, on simplification, the terms of the expansion are:

(a+b)^n  ={n \choose 0}a^{(n)}b^{(0)} + {n \choose 1}a^{(n-1)}b^{(1)} + {n \choose 2}a^{(n-2)}b^{(2)} + .....  +{n \choose n}a^{(0)}b^{(n)}

The above statement holds for each  n > 0

Hence, the complete expansion for the given expression is given as above.

4 0
3 years ago
Read 2 more answers
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