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prisoha [69]
2 years ago
12

From a population of 200,000,000 elements, the standard deviation is known to be 14. A sample of 49 elements is selected. It is

determined that the sample mean is 56. The standard error of the mean is
Mathematics
1 answer:
Talja [164]2 years ago
4 0

Answer:

The standard error of the mean = 2

Step-by-step explanation:

Given that:

The standard deviation σ = 14

The sample size n = 49

The sample mean \overline x = 56

The formula for calculating the standard error can be expressed as:

S.E = \dfrac{\sigma}{\sqrt{n}}

S.E = \dfrac{14}{\sqrt{49}}

S.E = \dfrac{14}{7}

S.E = 2

Therefore, the standard error of the mean = 2

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Answer:

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7 0
2 years ago
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What is the answer to this math problem​
vesna_86 [32]

Hello from MrBillDoesMath!

Answer:

1/243

Discussion:  

3^(-3) *  3^(-2)                => as a^m * a^n = a^(m+n), the exponents add

= 3^ (-3 -2)

= 3^ (-5) =

= 1/ 3^5                           => as 3^5 = 243

= 1/243

which is approximately  .0041

Thank you,

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7 0
3 years ago
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This is Hard for me!
max2010maxim [7]
DIFFERENTIATION
6+f(28+b(4)=6+112f+4bf
b=6+112f/-4f
b=1*6^0+1*112f^0/1*-4f^0
b=1+1/1
b=2
8 0
3 years ago
Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables.
Pepsi [2]

Answer:

x=20

y=10\,\sqrt{3}

Step-by-step explanation:

In the triangle we have the following trigonometric equations:

tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}

and also:

cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20

8 0
3 years ago
Consider m = y2 - y1/ x2 - x1 . Which x1 and x2-values would determine that the line is vertical? Justify your answer
Y_Kistochka [10]

Answer:

x_2=x_1

Step-by-step explanation:

We were given the slope formula;

m=\frac{y_2-y_1}{x_2-x_1}

This line is vertical if the denominator is zero.

That is when x_2-x-1=0

This implies that;

x_2=x_1

Justification;

When x_2=x_1, then, the line passes through;

(x_1,y_1)  and (x_1,y_2)

The slope now become

m=\frac{y_2-y_1}{x_1-x_1}=\frac{y_2-y_1}{0}

The equation of the line is

y-y_1=\frac{y_2-y_1}{0}(x-x_1)

This implies that;

0(y-y_1)=(y_2-y_1)(x-x_1)

0=(y_2-y_1)(x-x_1)

\frac{0}{y_2-y_1}=(x-x_1)

0=(x-x_1)

x=x_1... This is the equation of a vertical line.

3 0
2 years ago
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