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Sergeeva-Olga [200]
3 years ago
11

Prove that ABCD is a rectangle. A = (-4, 4) B = (0,5) C = (1, 1) D = (-3,0)

Mathematics
2 answers:
kaheart [24]3 years ago
5 0

Answer:

Draw it on a graph sheet

AURORKA [14]3 years ago
4 0
The easiest way to prove it is to show it on a graph paper
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Find the slope please
inysia [295]

Answer:

-1/3

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solve 5c + 4 = -26
mr_godi [17]
<em>1) 5 c + 4 = - 26
5 c = -26 -4
5 c = -30
c = -30 / 5
c = -6    so correct option is B..

2) 3 x - x +2 = 12
2 x +2 = 12
2x = 12-2
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x = 10/2
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3 ) 3 ( x + 1 )+ 6 = 33
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3x = 33-9
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x = 24/3
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4) y/-6=9
y=9 x -6
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5)(x +  4) /2 = 7
x +4 = 7 x 2
x + 4 = 14
x = 14-4
x = 10  so correct option is D

6)1/3 ( 2x - 8) = 4
2x/ 3 - 8 /3 = 4
2x - 8 / 3 = 4
2x - 8 = 4 x 3
2x - 8 = 12
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x = 20/2
x = 10   so correct option is C


</em>
6 0
4 years ago
What is the value of the 3 in 8.139
Fofino [41]

The 8 is in the ones place.

The 1 is in the tenths place.

The 3 is in the hundredths place.

The 9 is in the thousandths place.

hope it helps!

6 0
3 years ago
Use long division to find the quotient. <br><br>(x²+6x-27) ÷ (x-3)
Alex
\frac{ x^2+6x-27 }{x-3} = \frac{ x^2+6x +3x-3x-27 }{x-3} = \frac{ x^2+9x-3x-27 }{x-3} = \\ \\ =\frac{ x(x +9 )-3(x+9) }{x-3} = \frac{ (x +9 ) (x-3) }{x-3} = x+9 \\ \\ \\ x-3\neq 0 \\x\neq 3\\D=R\setminus \left \{ 3 \right \}


4 0
3 years ago
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