Consider, in ΔRPQ,
RP = R (Radius of larger circle)
PQ = r (radius of smaller circle)
We have to find, RQ, by Pythagoras theorem,
RP² = PQ²+RQ²
R² = r²+RQ²
RQ² = R²-r²
RQ = √(R²-r²
Now, as RQ & QS both are tangents of the smaller circle, their lengths must be equal. so, RS = 2 × RQ
RS = 2√(R²-r²)
Answer:
Alison turns on the water and allows it to run in the tub for a few minutes. She then turns the water off while she runs to answer the front door. Alison comes back and allows water to run into the tub for a couple more minutes before she takes a short bath. After the bath, Alison allows the water to completely drain from the tub.
Step-by-step explanation:
took the k12 test hope this helps
