All categories

3 years ago

Please help what's the correct ordered pair

Mathematics

2 answers:

Vanyuwa [196]3 years ago

7 0

I belive it is A 6,9 but i am not entirely sure.

max2010maxim [7]3 years ago

3 0

A, 6’9 !! Comment for an explanation

You might be interested in

the equation 4(x+9)=76 models this situation which choice shows the sequence of operations neede to slove this problem using bot

laiz [17]

Answer:

Step-by-step explanation:

Here you go mate

Use PEMDAS

Parenthesis,Exponent,Multiplication,Division,Addition,Subtraction

Step 1

4(x+9)=76 Equation/Question

Step 2

4(x+9)=76 Remove parenthesis by multiplying 4

4x+36=76

Step 3

4x+36=76 Subtract 36 from sides

4x=40

Step 4

4x=40 Divide sides by 4

answer

x=10

Hope this helps

5 0

3 years ago

Which value is NOT a solution of 8x3 – 1 = 0?

Tpy6a [65]

<u><em>Note: As you may have unintentionally missed to add the value choices. But, I would make sure to explain the concept so that you may improve your understanding in terms of solving these type of questions.</em></u>

Answer:

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Step-by-step explanation:

Considering the equation

$8x^3\:-\:1\:=\:0$

Steps to solve the equation

$8x^3-1=0$

$\mathrm{Add\:}1\mathrm{\:to\:both\:sides}$

$8x^3-1+1=0+1$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{Divide\:both\:sides\:by\:}8$

$\frac{8x^3}{8}=\frac{1}{8}$

$\mathrm{Simplify}$

$x^3=\frac{1}{8}$

$\mathrm{For\:}x^3=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt[3]{f\left(a\right)},\:\sqrt[3]{f\left(a\right)}\frac{-1-\sqrt{3}i}{2},\:\sqrt[3]{f\left(a\right)}\frac{-1+\sqrt{3}i}{2}$

$x=\sqrt[3]{\frac{1}{8}},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1+\sqrt{3}i}{2},\:x=\sqrt[3]{\frac{1}{8}}\frac{-1-\sqrt{3}i}{2}$

So,

$x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$

Therefore,

Any value other than the values $x=\frac{1}{2},\:x=-\frac{1}{4}+i\frac{\sqrt{3}}{4},\:x=-\frac{1}{4}-i\frac{\sqrt{3}}{4}$ will not be a solution of $8x^3\:-\:1\:=\:0$ .

Keywords: solution, value

Learn more about equation solution from brainly.com/question/1679491

#learnwithBrainly

7 0

3 years ago

Lee needed to make drapes the length from the floor to the top of the window. The wall beneath the window had the height of 2 2/

Tatiana [17]

Since drapes have to be covered all over the window and the beneath of the window, both lengths have to be added.

(2 2/3) + ( 2 3/4)
(8/3) + (11/4)
(32+33)/12
65/12
5 5/12

7 0

3 years ago

I need help doings this

julia-pushkina [17]

Answer:

Either A or C, I'm not quite sure tho

Step-by-step explanation:

The line is on the negative side of the graph

6 0

3 years ago

Help me help me help me

Vinil7 [7]

Answer:

40 dollars the answer is 40!!!

6 0

3 years ago