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Archy [21]
3 years ago
13

Find the image of the given point

Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
6 0

Answer:

P' = (2, -6)

Step-by-step explanation:

In this translation, you just need to substitute x and y into the given translation to find what P' is. (x is -6 since it's the x-value of P, and y is -2 since it's the y-value of P):

where T(x, y) = (x + 8, y - 4) and x = -6 and y = -2,

T(-6, -2) = ((-6) + 8), (-2) - 4) (substitute x and y into the translation)

T(-6, -2) = (2, -6) (add and subtract)

So, P' = (2, -6)

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HELP HURRYYY!!! I DONT KNOW
Anettt [7]

Answer:

it would be A. it would be A because on the x coordinate would be placed like (x, y) 4 is negative and 6 is positive, hence (-4, 6)

Step-by-step explanation:

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5 0
3 years ago
Which other parts must be equal for triangle ABC= triangle MTR by
lesya692 [45]

Answer:

see below

Step-by-step explanation:

ASA stands for <u>Angle</u><u>-side-Angle</u>

thus, for ∆ABC\cong∆MTR

\displaystyle  \angle C  \cong  \angle R

SAS stands for <u>Side-angle-Side </u>

thus,for ∆ABC\cong∆MTR

\displaystyle \overline{  MR }\cong  \overline{MT}

likewise,

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7 0
3 years ago
The plan shows part of a roof on a house. A horizontal beam parallel to the base of the roof connects the roof and the central p
gulaghasi [49]
Pls. see attachment.

6 0
4 years ago
Pls help !!
olga55 [171]

Area of circle= πr² so, our radius would be 5in because the diameter is 10 in which makes our sum to be π×5²= 78.5 in

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7 0
4 years ago
Read 2 more answers
At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the firs
rewona [7]

Answer:

4032 different tickets are possible.

Step-by-step explanation:

Given : At a race track you have the opportunity to buy a ticket that requires you to pick the first and second place horses in the first two races. If the first race runs 9 horses and the second runs 8.

To find : How many different tickets are possible ?

Solution :

In the first race there are 9 ways to pick the winner for first and second place.

Number of ways for first place - ^9C_1=9

Number of ways for second place - ^8C_1=8

In the second race there are 8 ways to pick the winner for first and second place.

Number of ways for first place - ^8C_1=8

Number of ways for second place - ^7C_1=7

Total number of different tickets are possible is

n=9\times 8\times 8\times 7

n=4032

Therefore, 4032 different tickets are possible.

8 0
3 years ago
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