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4 years ago

Find the LCM and HCF of 12 and 15.

2 answers:

german4 years ago

6 0

HCF: is 3
LCM: is 60
That’s bc..
12: 1,2,3,4,6,12
15:1,3,5,15
So the HCF is 3

12: 12,24,36,48,60 etc.
15: 15,30,45,60 etc.
So the LCM is 60

Hope this helped u

larisa [96]4 years ago

4 0

LCM: 3
HCF: 60

I think

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Please help me with this!:((

Studentka2010 [4]

Answer:

C. II only

Step-by-step explanation:

A rational number is a terminating decimal, meaning that the decimal does not go on forever.

I and III have ellipses (...) after them, meaning they are a nonterminating decimal, so these are irrational numbers.

II has a decimal that ends, so II is a rational number.

7 0

3 years ago

Ari is taking a group of people to the movies. Each child costs $4 and each adult is $9. How much will he pay if the group consi

alexira [117]

Dur

4 kids cost 4 each, total is 4 times 4 or 16 for kids

adult is 9
3 of them
3 times 9=27

kids+adults=16+27=$43

3 0

3 years ago

Read 2 more answers

Tom has deposited $500 in an account which earns 2% interest each year. Which expression correctly shows the total value of his

nignag [31]

It's D
500+3×0.02×500=530

3 0

3 years ago

A store owner paid $20 for a book. She marked up the price of the book by 15% to determine its selling price. What is the sellin

TiliK225 [7]

Answer:

20 : 100% = x : 115%

Step-by-step explanation:

Do 115 x 20

divide the answer by 100

and that is your answer

8 0

3 years ago

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft and on the other three s

makvit [3.9K]

Answer:

The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = $Length \times Breadth = xy$

We are given that the area of the garden is 122 square feet

So, $xy=122$ ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

Total cost = 30x+20y

Substitute the value of y from A

Total cost = $30x+20(\frac{122}{x})$

Total cost = $\frac{2440}{x}+30x$

Now take the derivative to minimize the cost

$f(x)=\frac{2440}{x}+30x$

$f'(x)=-\frac{2440}{x^2}+30$

Equate it equal to 0

$0=-\frac{2440}{x^2}+30$

$\frac{2440}{x^2}=30$

$\sqrt{\frac{2440}{30}}=x$

$9.018 =x$

Now check whether it is minimum or not

take second derivative

$f'(x)=-\frac{2440}{x^2}+30$

$f''(x)=-(-2)\frac{2440}{x^3}$

Substitute the value of x

$f''(x)=-(-2)\frac{2440}{(9.018)^3}$

$f''(x)=6.6540$

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

$(9.018)y=122$

$y=\frac{122}{9.018}$

$y=13.528$

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

4 0

3 years ago