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3 years ago

Simply this fully. Please quick

Mathematics

1 answer:

sattari [20]3 years ago

7 0

Answer:

$\frac{x^{2} -2x}{15}$

Step-by-step explanation:

$\frac{2x-4}{5} \times \frac{x}{6}$

Multiply numerators and denominators

$\frac{x(2x-4)}{5 \times 6}$

Taking two common from numerator

$\frac{x(x-2)}{5 \times 3}$

Simplifying it further

$\frac{x^{2} -2x}{15}$

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Answer:

AC < BC < AB

Step-by-step explanation:

Given: BC = 118

AB = 63*2 = 126

AC = 360 - (BC+AB)

AC = 360 - (118+126) = 116

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2 years ago

Given line segment AB, the coordinates of A are (3,-5) and the coordinates midpoint are (5,-1), what are the coordinates for B?

dsp73

Answer:

Step-by-step explanation:

Point P(5, -1) being the midpoint of AB means that $x_P-x_A=x_B-x_P$

$5-3=x_B-5\\\\2+5=x_B\\\\x_B=7$

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3 years ago

A sector of a circle makes a 127° angle at its centre. If the arc of the sector has length 36 mm, find

Veseljchak [2.6K]

Answer:

Approximately $68.5\; \rm mm$ .

Step-by-step explanation:

Convert the angle of this sector to radians:

$\begin{aligned}\theta &= 127^{\circ} \\ &= 127^{\circ} \times \frac{2\pi}{360^{\circ}} \\ &\approx 2.22\end{aligned}$ .

The formula $s = r\, \theta$ relates the arc length $s$ of a sector of angle $\theta$ (in radians) to the radius $r$ of this sector.

In this question, it is given that the arc length of this sector is $s = 36\; \rm mm$ . It was found that $\theta = 2.22$ radians. Rearrange the equation $s = r\, \theta$ to find the radius $r$ of this sector:

$\begin{aligned} r&= \frac{s}{\theta} \\ &\approx \frac{36\; \rm mm}{2.22} \\ &\approx 16.2\; \rm mm\end{aligned}$ .

The perimeter of this sector would be:

$\begin{aligned}& 2\, r + s \\ =\; & 2 \times 16.2\; {\rm mm} + 36\; {\rm mm} \\ =\; & 68.5\; \rm mm\end{aligned}$ .

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3 years ago

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3 years ago

A ladder is 74 inches tall. How tall is it in feet and inches?

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Step-by-step explanation:

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3 years ago

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