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Gemiola [76]
2 years ago
8

Explain what each of the numbers -10, -20, and -30 tell you about acount 5.

Mathematics
1 answer:
Nataly [62]2 years ago
6 0
They are multiples of 5
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A rectangular prism has a base with a length of 25, a width of 9, and a height of 12. A second prism has a square base with a si
RSB [31]

Answer:

The height of the second prism is 12 units.

Step-by-step explanation:

First, we must know that the volume of a rectangular prism is equal to length x width x height. With this information, we can multiply the given dimensions of the first rectangular prism to get a volume of 2700 cubic units. From here, we must understand wha we need from the second rectangular prism. Because it has a square base of 15, that accounts for both its width and length. Therefore, we have that

Volume= 15^2 x\\2700/225=x\\12=x

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2 years ago
Answers with links will be reported
Ber [7]

Answer:

11 months

Step-by-step explanation:

the math that i did was i kept adding 400 to 2500 and counted every four hundred that i added witch was 11 until i got to 7000 so the answer is 11 months. You will have some left over which you will have 300 left over.

8 0
3 years ago
How do u solve proportion equations
jok3333 [9.3K]
You draw a line and then a = and another line on another side


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3 years ago
If a hypothesis test leads to the rejection of the null hypothesis, a _____.
Butoxors [25]

Answer:

Step-by-step explanation:

Hope it helped u

6 0
2 years ago
Suppose x=c1e−t+c2e3tx=c1e−t+c2e3t. Verify that x=c1e−t+c2e3tx=c1e−t+c2e3t is a solution to x′′−2x′−3x=0x′′−2x′−3x=0 by substitu
Harrizon [31]

The correct question is:

Suppose x = c1e^(-t) + c2e^(3t) a solution to x''- 2x - 3x = 0 by substituting it into the differential equation. (Enter the terms in the order given. Enter c1 as c1 and c2 as c2.)

Answer:

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

Step-by-step explanation:

We need to verify that

x = c1e^(-t) + c2e^(3t)

is a solution to the differential equation

x''- 2x' - 3x = 0

We differentiate

x = c1e^(-t) + c2e^(3t)

twice in succession, and substitute the values of x, x', and x'' into the differential equation

x''- 2x' - 3x = 0

and see if it is satisfied.

Let us do that.

x = c1e^(-t) + c2e^(3t)

x' = -c1e^(-t) + 3c2e^(3t)

x'' = c1e^(-t) + 9c2e^(3t)

Now,

x''- 2x' - 3x = [c1e^(-t) + 9c2e^(3t)] - 2[-c1e^(-t) + 3c2e^(3t)] - 3[c1e^(-t) + c2e^(3t)]

= (1 + 2 - 3)c1e^(-t) + (9 - 6 - 3)c2e^(3t)

= 0

Therefore, the differential equation is satisfied, and hence, x is a solution.

4 0
3 years ago
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