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amm1812
3 years ago
12

What type of essay would be written in f chronological order​

Mathematics
2 answers:
bonufazy [111]3 years ago
7 0

Answer:

It arranges information according to time. In composition and speech, chronological order is a method of organization in which actions or events are presented as they occur or occurred in time and can also be called time or linear order. Narratives and process analysis essays commonly rely on chronological order.

Ex:

First we went to the supermarket, Then we went to a friends house, lastly we went home to get some rest and watch TV.

Ostrovityanka [42]3 years ago
3 0

Answer:

D

Step-by-step explanation:

I had this on a quiz- So I think its right- if not then I'm not sure

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Arisa [49]

Answer:

15

Step-by-step explanation:

x³ - (3 + x)²

4³ - (3 + 4)²

8 0
3 years ago
A regulation soccer goal net is 24 ft wide by 8 ft high. A soccer net for children is 6 ft wide. If the manufacturer wishes to k
oksian1 [2.3K]
If the regular soccer goal was 24 ft wide and the kid soccer goal was 6 ft wide 6x4=24 so if you would do the same thing to the height the kid soccer goal would be 2 ft tall
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3 years ago
A game board with 17 spaces. Start, green, green, star, quesiton mark, question mark, star, question mark, green, cat town, gree
erastova [34]

Answer:

Possibly the answer is 2 green spaces, 2 star spaces, 3 question mark spaces

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
CD contains the points C at 4, D at 0, and E at 2.
horsena [70]

Answer:

the length of CD is 4

the length of DE is 2

the ratio of CD to DE is 2:1

Step-by-step explanation:

8 0
3 years ago
What are the solutions of the quadratic equation (x + 3)(x +3) = 49? Ax = -2 and x = -16 Bx = 2 and x = -10 Cx = 4 and x = -10 D
Ivahew [28]

Answer:

4 and -10

Step-by-step explanation:

\displaystyle (x + 3)(x +3) = 49 \\ x^2+3x+3x+9=49 \\ x^2 +6x+9=49 \\ x^2 + 6x + 9 - 49 = 0 \\x^2+6x-40=0 \\\\ \Delta=b^2-4ac \\ \Delta=6^2-4 \cdot 1 \cdot (-40) \\ \Delta=36+160 \\ \Delta=196 \\ \\ X_{1,2}=\frac{-b \pm \sqrt{\Delta} }{2a}  \\ \\ X_1=\frac{-b+\sqrt{\Delta} }{2a} = \frac{-6+14}{2} = \frac{8}{2}=4 \\ \\ X_2=\frac{-b-\sqrt{\Delta} }{2a}  = \frac{-6-14}{2}=\frac{-20}{2} = -10

4 0
3 years ago
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