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4 years ago

What function can be used to model data pairs that have a common ratio?

Mathematics

2 answers:

I am Lyosha [343]4 years ago

7 0

Answer:

Option C. exponential

Step-by-step explanation:

"Common Ratio" is the term always used in geometric sequence which is in the exponential form.

We can write the function defined by exponential as

$f(x)=r^{n}$

Where r is the common ratio and n is denoting number of terms.

Now if we plug in the values of n as 1, 2, 3, 4

The sequence will be $r^{1}, r^{2}, r^{3}, r^{4}$ and so on.

Therefore the exponential function can be used to model data pairs that have a common ratio.

liubo4ka [24]4 years ago

4 0

Correct answer is C.

For example 2, 4, 8, 16, 32...

$2=\frac{4}{2} = \frac{8}{4} = \frac{16}{8} = \frac{32}{16} =...$

$y=2^x$

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311 students went on a field trip. Six buses were

kow [346]

Answer:

50.6

Step-by-step explanation:

it says 7 students traveled by car so you need to take 7 from 311, then divide your answer (304) by 6, which is 50.6

5 0

3 years ago

Read 2 more answers

Solve each system of inequalities by graphing. x>2 y<4

Snowcat [4.5K]

Answer:

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

A pro basketball player is a poorâ free-throw shooter. Consider situations in which he shoots a pair of free throws. The probabi

zlopas [31]

Answer:

The probability that he makes one of the two free throws is 0.38

Step-by-step explanation:

Hello!

Considering the situation:

A pro basketball player shoots two free throws.

The following events are determined:

A: "He makes the first free throw"

Ac: "He doesn't make the first free throw"

B: "He makes the second free throw"

Bc: "He doesn't make the second free throw"

It is known that

P(A)= 0.48

P(B/A)= 0.62

P(B/Ac)= 0.38

You need to calculate the probability that he makes one of the two free throws.

There are two possibilities, that "he makes the first throw but fails the second" or that "he fails the first throw and makes the second"

Symbolically:

P(A∩Bc) + P(Ac∩B)

P(A)= 0.48

P(Ac)= 1 - P(A)= 1 - 0.48= 0.52

P(Ac∩B) = P(Ac) * P(B/Ac)= 0.52*0.38= 0.1976≅ 0.20

P(A∩B)= P(A)*P(B/A)= 0.48*0.62= 0.2976≅ 0.30

P(A)= P(A∩B) + P(A∩Bc)

P(A∩Bc)= P(A) - P(A∩B)= 0.48 - 0.30= 0.18

Step 3

P(Ac∩B) + P(A∩Bc) = 0.20 + 0.18= 0.38

I hope this helps!

8 0

3 years ago

Suppose the probability of a false positive result on a mammogram is 4%. Suppose that the probability of a false negative result

Mariulka [41]

Answer:

0.0049 = 0.49% probability that she actually has breast cancer

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test result

Event B: Breast cancer

Probability of a positive test result:

4% of (1 - 0.0002)

98% of 0.0002

$P(A) = 0.04*(1 - 0.0002) + 0.98*0.0002 = 0.040188$

Having breast cancer and testing positive.

98% of 0.0002

$P(A \cap B) = 0.98*0.0002 = 0.000196$

What is the probability that she actually has breast cancer?

$P(B|A) = \frac{0.000196}{0.040188} = 0.0049$

0.0049 = 0.49% probability that she actually has breast cancer

8 0

3 years ago

You take out a loan for $550 at a rate of 4.5% for 3 years. At the end of 3 years, how much interest has accumulated on the loan

shusha [124]

550 * 4.5% = 24.75

24.75 * 3 = 74.25

The loan has accumulated to $74.25

The total paid back would be $624.25

Hope I could help :)

3 0

3 years ago