What is 23+41-7×398-15
1 answer:
This question is just a type of question that you honestly just need to punch into a calculator. However, if you just do a simple one-over-one addition of 23 and 41, then subtract, it gets even easier. Then, do another one-over-one but this time as subtraction when you take away the 7. Then you will do yet another one-over-one but for multiplication with your sum of your numbers after subtraction. Finally, do another one-over-one to get your final answer of 22,671. I will attach a picture of what this looks like as well as an illustrated one-over-one. Hope this helped!
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Step-by-step explanation:
We have
First, 125 is a perfect cube because
and
x^3 is a perfect cube because
so we can use the difference of cubes identity
Let say we have two perfect cubes:
64 because 8×8×8=64
and 27 because 3×3×3=27 and let subtract
we know that
but using the difference of cubes identity we should get the same thing.
Remeber cube root of 64 is 4 and cube root of 27 is 3 so we have
So the difference of cubes works for real numbers. This is a good way to help remeber the identity using real numbers.
Back on to the topic,
we know that 5 is cube root of 125 and x is the cube root of x^3 so we have