The formula for the area of the shaded region in the figure.
x² = 4py is mathematically given as

<h3>What is the formula for the area of the shaded region in the figure?</h3>
Parameters



Generally, the equation for the Area is mathematically given as
![& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\](https://tex.z-dn.net/?f=%26%20A%3D2%20%5Cint_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%5Cleft%28h-%5Cfrac%7Bx%5E%7B2%7D%7D%7B4%20p%7D%5Cright%29%20d%20x%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%28h%20x-%5Cfrac%7Bx%5E%7B3%7D%7D%7B12%20p%7D%5Cright%5D_%7B0%7D%5E%7B2%20%5Csqrt%7Bp%20h%7D%7D%20%5C%5C%5C%5C%26%20A%3D2%5Cleft%5B%5Cleft%5Bh%202%20%5Csqrt%7Bp%20h%7D-%5Cfrac%7B1%7D%7B12%20p%7D%20%5Ccdot%282%20%5Csqrt%7Bp%20h%7D%29%5E%7B3%7D-0%5Cright%5D%5Cright.%20%5C%5C)
![&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h](https://tex.z-dn.net/?f=%26A%3D2%5Cleft%5B2%20h%5E%7B3%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B8%28%5Csqrt%7Bp%7D%29%5E%7B3%7D%28%5Csqrt%7Bh%7D%29%5E%7B3%7D%7D%7B12%20p%7D-0%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%5Cleft%5B2%20h%5E%7Bk%20%2F%202%7D%20%5Csqrt%7Bp%7D-%5Cfrac%7B2%7D%7B3%7D%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%5Cright%5D%20%5C%5C%5C%5C%26A%3D2%20%5Ctimes%20%5Cfrac%7B4%20%5Csqrt%7Bp%7D%20%5Ccdot%20h%5E%7B3%20%2F%202%7D%7D%7B3%7D%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Ccdot%20%5Csqrt%7Bp%7D%20%5Ccdot%20%5Csqrt%7Bh%7D%20%5Ccdot%20h%20%5C%5C%5C%5C%26A%3D%5Cfrac%7B8%7D%7B3%7D%20%5Csqrt%7Bp%20h%7D%20%5Ccdot%20h)

In conclusion, the equation for the Area is

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Answer:
The scale factor is 3
Step-by-step explanation:
6/2=3 (one of the triangles sides)
Answer:173/10
Step-by-step explanation:
The temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C
From Newton's law of cooling, we have that

Where





From the question,


∴ 

Therefore, the equation
becomes

Also, from the question
After 1 hour, the temperature of the ice-cream base has decreased to 58°C.
That is,
At time
, 
Then, we can write that

Then, we get

Now, solve for 
First collect like terms


Then,


Now, take the natural log of both sides


This is the value of the constant 
Now, for the temperature of the ice cream 2 hours after it was placed in the freezer, that is, at 
From

Then






Hence, the temperature of the ice cream 2 hours after it was placed in the freezer is 37.40 °C
Learn more here: brainly.com/question/11689670
A = wl
Simply divide both sides by w. This is done to isolate the variable we are solving for.
A/w = (wl)/w
A/w = l
Answer: Choice C