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Nata [24]
3 years ago
10

12 POINTS! WILL MARK BRAINIEST! IF YOU TAKE THE POINTS I WILL REPORT PLEASE ASAP! QUESTION IN PIC

Mathematics
1 answer:
tamaranim1 [39]3 years ago
3 0
6-9y. The fourth choice
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Question is in the photo​
blagie [28]

9514 1404 393

Answer:

  ∠D = 68°

Step-by-step explanation:

In a quadrilateral that is inscribed in a circle, opposite angles are supplementary.

  ∠D = 180° - ∠B

  ∠D = 180° -112°

  ∠D = 68°

4 0
3 years ago
What method would be the easiest to solve this equation?
Advocard [28]

Answer:

1, -6

Step-by-step explanation:

Easiest is just to factor

(x+1)(x-6)=0

7 0
3 years ago
Read 2 more answers
What is 5x + 7 < 22 on a number line​
kozerog [31]

Answer:

x < 3

Step-by-step explanation:

5x + 7 < 22 \\ 5x < 22 - 7 \\ 5x < 15 \\ x  <  \frac{15}{5}  \\ x < 3

3 0
3 years ago
What does y = 5/4x - 2 y = -1/4x + 19 equal
emmasim [6.3K]

Answer:

The solution is at the point (14, 15.5)

Step-by-step explanation:

I graphed the equations on the graph below.

If this answer is correct, please make me Brainliest!

5 0
3 years ago
A box contains 11 red chips and 4 blue chips. We perform the following two-step experiment: (1) First, a chip is selected at ran
Scilla [17]

Answer:

P(B1) = (11/15)

P(B2) = (4/15)

P(A) = (11/15)

P(B1|A) = (5/7)

P(B2|A) = (2/7)

Step-by-step explanation:

There are 11 red chips and 4 blue chips in a box. Two chips are selected one after the other at random and without replacement from the box.

B1 is the event that the chip removed from the box at the first step of the experiment is red.

B2 is the event that the chip removed from the box at the first step of the experiment is blue. A is the event that the chip selected from the box at the second step of the experiment is red.

Note that the probability of an event is the number of elements in that event divided by the Total number of elements in the sample space.

P(E) = n(E) ÷ n(S)

P(B1) = probability that the first chip selected is a red chip = (11/15)

P(B2) = probability that the first chip selected is a blue chip = (4/15)

P(A) = probability that the second chip selected is a red chip

P(A) = P(B1 n A) + P(B2 n A) (Since events B1 and B2 are mutually exclusive)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/21) + (22/105) = (77/105) = (11/15)

P(B1|A) = probability that the first chip selected is a red chip given that the second chip selected is a red chip

The conditional probability, P(X|Y) is given mathematically as

P(X|Y) = P(X n Y) ÷ P(Y)

So, P(B1|A) = P(B1 n A) ÷ P(A)

P(B1 n A) = (11/15) × (10/14) = (11/21)

P(A) = (11/15)

P(B1|A) = (11/21) ÷ (11/15) = (15/21) = (5/7)

P(B2|A) = probability that the first chip selected is a blue chip given that the second chip selected is a red chip

P(B2|A) = P(B2 n A) ÷ P(A)

P(B2 n A) = (4/15) × (11/14) = (22/105)

P(A) = (11/15)

P(B2|A) = (22/105) ÷ (11/15) = (2/7)

Hope this Helps!!!

5 0
3 years ago
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