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fgiga [73]
3 years ago
9

Write an equation of the line perpendicular to the given line that contains P

Mathematics
1 answer:
Aleksandr [31]3 years ago
8 0
I believe you are missing either a function or a graph here
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Please help! Correct Answers only!
denpristay [2]

Answer:

Using the given formula:

I = P × R ×T

I = 40000 × 15/100 × 2

I = $12000

3 0
2 years ago
What is the slope of each side of the triangle? the sides are A(-2,4) B(-1,1) C(2,3)
Rashid [163]

Answer:

The slopes of three sides of triangle are as follows:

AB = -3

BC = 2/3

AC = -1/4

Step-by-step explanation:

The slope is denoted by m and is calculated using the formula

m = \frac{y_2-y_1}{x_2-x_1}

The given vertices are:

A(-2,4) B(-1,1) C(2,3)

The sides will be:

AB, BC, AC

Let m1 be the slope of AB

Let m2 be the slope of BC

Let m3 be the slope of AC

Now

Slope\ of\ AB = m_1 = \frac{1-4}{-1+2} = \frac{-3}{1} = -3\\Slope\ of\ BC = m_2 = \frac{3-1}{2+1} = \frac{2}{3}\\Slope\ of\ AC = m_2 = \frac{3-4}{2+2} = \frac{-1}{4} = -\frac{1}{4}

Hence,

The slopes of three sides of triangle are as follows:

AB = -3

BC = 2/3

AC = -1/4

6 0
2 years ago
The length of a rectangle is three times its width.
Igoryamba
96 divided by 4 is 24
3times 24 is72
And 72 is 3 times 24
And 72plus 24 is 96
So your answer is length 72
Wide24
8 0
2 years ago
Write the equation of the parabola that has its x-intercepts at (1+<img src="https://tex.z-dn.net/?f=%5Csqrt%7B5%7D" id="TexForm
VladimirAG [237]

Answer:

y=2x^2-4x-8

Step-by-step explanation:

<u>Factored form of a parabola</u>

y=a(x-p)(x-q)

where:

  • p and q are the x-intercepts.
  • a is some constant.

Given x-intercepts:

  • (1+√5, 0)
  • (1-√5, 0)

Therefore:

\implies y=a(x-(1+\sqrt{5}))(x-(1-\sqrt{5}))

\implies y=a(x-1-\sqrt{5})(x-1+\sqrt{5})

To find a, substitute the given point (4, 8) into the equation and solve for a:

\implies a(4-1-\sqrt{5})(4-1+\sqrt{5})=8

\implies a(3-\sqrt{5})(3+\sqrt{5})=8

\implies4a=8

\implies a=2

Therefore, the equation of the parabola in factored form is:

\implies y=2(x-1-\sqrt{5})(x-1+\sqrt{5})

Expand so that the equation is in standard form:

\implies y=2(x^2-x+\sqrt{5}x-x+1-\sqrt{5}-\sqrt{5}x+\sqrt{5}-5)

\implies y=2(x^2-x-x+\sqrt{5}x-\sqrt{5}x+\sqrt{5}-\sqrt{5}+1-5)

\implies y=2(x^2-2x-4)

\implies y=2x^2-4x-8

6 0
1 year ago
Someone please help 5 points.
choli [55]

Answer:

7.1 I am pretty sure okay cya

4 0
3 years ago
Read 2 more answers
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