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3 years ago

The length of the hypotenuse of a 30°-60°-90° triangle is 30 meters. Find the length of the side opposite the 30° angle

Mathematics

1 answer:

olchik [2.2K]3 years ago

4 0

Adjacent side is 26meters
Opposite side is 15meters

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3 years ago

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This equation represents an exponential function that passes through the point (2, 80).

miss Akunina [59]

we know that

If the point belongs to the graph, then the point must satisfy the equation

we will proceed to verify each case

case A.) $f(x)=4(x^{5})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=4(2^{5})$

$f(2)=128$

$128\neq 80$

therefore

the equation $f(x)=4(x^{5})$ not passes through the point $(2,80)$

case B.) $f(x)=5(x^{4})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=5(2^{4})$

$f(2)=80$

$80=80$

therefore

the equation $f(x)=5(x^{4})$ passes through the point $(2,80)$

case C.) $f(x)=4(5^{x})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=4(5^{2})$

$f(2)=100$

$100\neq 80$

therefore

the equation $f(x)=4(5^{x})$ not passes through the point $(2,80)$

case D.) $f(x)=5(4^{x})$

The point is $(2,80)$

Verify if the point satisfy the equation

For $x=2$ find the value of y in the equation and compare with the y-coordinate of the point

$f(2)=5(4^{2})$

$f(2)=80$

$80=80$

therefore

the equation $f(x)=5(4^{x})$ passes through the point $(2,80)$

therefore

the answer is

$f(x)=5(x^{4})$

$f(x)=5(4^{x})$

6 0

3 years ago

Read 2 more answers