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Goryan [66]
3 years ago
14

82. Subtract 12x? + 6y - 3 and 3x? - 9y + 12

Mathematics
1 answer:
balu736 [363]3 years ago
3 0

Answer:

-x^2+15y-15

Answer if it is a ^2

Step-by-step explanation:

2x^2 + 6y - 3 -(3x^2 - 9y + 12)=

2x^2+6y-3-3x^2+9y-12=

-x^2+15y-15

is it a ^2 or a question mark

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ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions
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<u>Step-by-step explanation:</u>

The vertex form of a quadratic equation is: y = a(x - h)² + k

where (h, k) is the vertex   ⇒    k is the maximum height

the distance traveled is when y = 0     ⇒    x=\sqrt{\dfrac{-k}{a}}+h

Given: H(t) = -7.1(t - 2.3)² + 98

maximum height (k) = 98 feet

distance traveled (x) = \sqrt{\dfrac{-98}{-7.1}}+2.3    = 6.02 seconds

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maximum height (k) = 112 feet

distance traveled (x) = \sqrt{\dfrac{-112}{-7.5}}+2.2    = 6.06 seconds

B) H(t) = -6.9(t - 2.3)² + 112

maximum height (k) = 112 feet

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C) H(t) = -6.9(t - 2.4)² + 95

maximum height (k) = 95 feet

This has a lower height than the given equation.

D) H(t) = -7.5(t - 2.3)² + 95

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Which literal equations are equivalent to ? Choose all answers that are correct.
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a.\\g=\frac{w}{m}\ \ \ \ |multiply\ both\ sides\ by\ m\neq0\\\\w=gm\ \boxed{c.}\\\\therefore:\boxed{a.}\ is\ equivalent\ to\ \boxed{c.}\\\\b.\\g=\frac{m}{w}\ \ \ \ |multiply\ both\ sides\ by\ w\neq0\\\\gw=m\ \ \ \ |divide\ both\ sides\ by\ g\neq0\\\\w=\frac{m}{g}\ \boxed{d.}\\\\therefore:\boxed{b.}\is\ equivalent\ to\ \boxed{d.}
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