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Dima020 [189]
3 years ago
7

Write the expression as a sum of a difference of cubes and factor it: 1/64m^3+1000

Mathematics
1 answer:
yarga [219]3 years ago
3 0

Answer:

(1\64m + 20) (1\4096m^2 - 5\322m + 100)

Step-by-step explanation:

use a^3 + b^3 = (a+b)(a^2 - ab + b^2) to factor the expression = (1\64m+10)(1\4096m^2 - 10\64m + 100)

reduce the fractions with 2 = (1\64m + 10)(1\4096m^2 - 5\32m + 100)

= (1\64m + 20) (1\4096m^2 - 5\322m + 100)

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4 0
3 years ago
A sample of 26 offshore oil workers took part in a simulated escape exercise, resulting in the accompanying data on time (sec) t
solniwko [45]

Answer:

The upper confidence bound for population mean escape time is: 379.27

The upper prediction bound for the escape time of a single additional worker  is 413.64

Step-by-step explanation:

Given that :

sample size n = 26

sample mean \bar x =  371.08

standard deviation \sigma = 24.45

The objective is to calculate an upper confidence bound for population mean escape time using a confidence level of 95%

We need to determine the standard error of these given data first;

So,

Standard Error S.E = \dfrac{\sigma }{\sqrt{n}}

Standard Error S.E = \dfrac{24.45 }{\sqrt{26}}

Standard Error S.E = \dfrac{24.45 }{4.898979486}

Standard Error S.E = 4.7950

However;

Degree of freedom df= n - 1

Degree of freedom df= 26 - 1

Degree of freedom df= 25

At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

Similarly;

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 4.7950

The Margin of error = 8.18986

The upper confidence bound for population mean escape time is = Sample Mean + Margin   of  Error

The upper confidence bound for population mean escape time is =  371.08 +  8.18986

The upper confidence bound for population mean escape time is = 379.26986  \approx 379.27

The upper confidence bound for population mean escape time is: 379.27

b.  Calculate an upper prediction bound for the escape time of a single additional worker using a prediction level of 95%.

The standard error of the mean = \sigma \times \sqrt{1+ \dfrac{1}{n}}

The standard error of the mean = 24.45 \times \sqrt{1+ \dfrac{1}{26}}

The standard error of the mean = 24.45 \times \sqrt{1+0.03846153846}

The standard error of the mean = 24.45 \times \sqrt{1.03846153846}

The standard error of the mean = 24.45 \times 1.019049331

The standard error of the mean = 24.91575614

Recall that : At confidence level of 95% and Degree of freedom df of  25 ;

t-value = 1.7080

∴

The Margin of error = t-value × S.E

The Margin of error = 1.7080 × 24.91575614

The Margin of error = 42.55611149

The upper prediction bound for the escape time of a single additional worker  is calculate by the addition of

Sample Mean + Margin of Error

= 371.08 + 42.55611149

= 413.6361115

\approx 413.64

The upper prediction bound for the escape time of a single additional worker  is 413.64

8 0
4 years ago
Sara can travel 23 feet in 11 hours. Please calculate Sara's rate of speed. (round to 2 decimal places)
kari74 [83]

Answer:

How do I ask a question on here?

Step-by-step explanation:

8 0
3 years ago
For question 24 please pick 1,2,3 or 4
Mama L [17]

Answer:

Line segment TS.

Step-by-step explanation:

We have an Unit Circle. The y-coordinate of T is the sine of \theta. Therefore, the exact value of \text{sin}(\theta) is TS.

T(\text{cos}(\theta),\text{sin}(\theta))

7 0
3 years ago
What is the equation of the line that passes through the points (6,-4 ) and (-8,-8 )?
Charra [1.4K]

Answer:

y = 2/7x - 40/7

Step-by-step explanation:

y2 - y1 / x2 - x1

-8 - (-4) / -8 - 6

-4/-14

= 2/7

y = 2/7x + b

-4 = 2/7(6) + b

-4 = 12/7 + b

-40/7

6 0
3 years ago
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