Question

Write the expression as a sum of a difference of cubes and factor it: 1/64m^3+1000

Answer 1

Answer:

(1\64m + 20) (1\4096m^2 - 5\322m + 100)

Step-by-step explanation:

use a^3 + b^3 = (a+b)(a^2 - ab + b^2) to factor the expression = (1\64m+10)(1\4096m^2 - 10\64m + 100)

reduce the fractions with 2 = (1\64m + 10)(1\4096m^2 - 5\32m + 100)

= (1\64m + 20) (1\4096m^2 - 5\322m + 100)