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2 years ago

Please help!! (Will give brainy!) (Geometry) (look at picture)

Mathematics

1 answer:

stiv31 [10]2 years ago

5 0

Answer:

First ones 90 and the second one is 48

Step-by-step explanation:

please brainliest me

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5. Factor x²-x-72 (x-8)(x+9) (x-6)(x+12) (x+6)(x-12) (x+8)(x-9)

Artyom0805 [142]

Answer:

(x + 8)(x - 9)

Step-by-step explanation:

(x+8)(x-9)

= x² - 9x + 8x - 72

= x² - x - 72

Then

The factorization of x² - x - 72 is (x+8)(x-9)

5 0

1 year ago

There are 40 flamingos at the zoo.if 3/4 of the flamingos are standing on one leg ,and the rest are standing on both legs. How m

mel-nik [20]

30 flamingo's are standing on one leg, 10 are standing on both legs
10x2=20+30=50
The answer is 50 legs

8 0

2 years ago

Read 2 more answers

A simplified form of 4x-4y 3x

Pavel [41]

7x-4y just combine all the x and all the y sice both the x here are positive you add them and there is only one y so just keep it as it is

4 0

2 years ago

72,43,15,66,32,72,52,19,28,81 find the Mean, median, mode, range

zlopas [31]

Answer:

66,77,52

Step-by-step explanation:

thats ny answer

7 0

2 years ago

Complete the equation of the line through (-9,-7) and (-6,-3)

Annette [7]

The equation of the line through (-9, -7) and (-6, -3) is $y+3=\frac{4}{3}(x+6)$

Solution:

Given, two points are (-9, -7) and (-6, -3)

We have to find that a line that passes through the given two points.

First let us find the slope of the line that passes through given two points.

The slope of the line "m" is given as:

$\mathrm{m}=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

$\text { where, }\left(x_{1}, y_{1}\right) \text { and }\left(x_{2}, y_{2}\right) \text { are two points on line. }$

So slope of our line $=\frac{-3-(-7)}{-6-(-9)}=\frac{-3+7}{-6+9}=\frac{4}{3}$

Now, let us find the line equation using point slope form:

$\mathrm{y}-\mathrm{y}_{1}=\mathrm{m}\left(\mathrm{x}-\mathrm{x}_{1}\right) \text { where } \mathrm{m} \text { is slope and }\left(\mathrm{x}_{1}, \mathrm{y}_{1}\right) \text { is point on the line. }$

By substituting the values we get,

$\text { Then, line equation } \rightarrow y-(-3)=\frac{4}{3}(x-(-6))$

$y+3=\frac{4}{3}(x+6)$

Hence, the line equation is $y+3=\frac{4}{3}(x+6)$

8 0

3 years ago