Answer:
-2
Step-by-step explanation:
We can find the slope of a line by using two points
(-2,1) and (2,-7)
The slope is given by
m = (y2-y1)/(x2-x1)
= (-7-1)/(2- -2)
= (-8)/(2+2)
= -8/4
=-2
Isolate the variable by dividing each side by the factors that don't contain the variable
v=2
What we have so far:
Kinetic energy = 0. The reason behind that is because the beam is not moving at a height of 40m.
Gavity, g = 9.8m/s²
Height = 40m
Potential energy = mgh; this is equal to 0 because m, stands for mass and in this problem, we do not have a value for the mass of the beam. Hence, 0 x 9.8m/s² x 40m = 0. Potential energy = 0.
Solution:
We will use the equation of Total energy:
TE = potential energy + kinetic energy
TE = 0 + 0
∴ TE = 0
The answer is: Assuming no air resistance, the total energy of the beam as it hits the ground is 0.
8.83176088663 is the answer
