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1 year ago

Combine any like terms in the expression. If there are no like terms, rewrite the expression.

Mathematics

1 answer:

stich3 [128]1 year ago

5 0

Answer:

40w^3

Step-by-step explanation:

I'm assuming you meant w^3 (w to the third power). In that case, you would just add 34 + 13 + 11 - 18 because they are all like terms (coefficients of w^3).

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DONT SEND A LINK TO DOWNLOAD A PIC IN THIS Is the relation shown a function? Explain.

horsena [70]

Answer:

no because there are more than 1 X inputs.

Step-by-step explanation:

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2 years ago

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What is the simplified expression for -2a^2b+a+a^2-5ab+3ab^2-b^2+2(a^2b+2ab)

Bas_tet [7]

a^2+a-ab+3ab^2-b^2 I hope this helps

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3 years ago

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Consider a prism with a height of 8 inches and a 14-inch by 14-inch square base, and a cylinder with a height of 10 inches and a

vekshin1

Answer:

782.5inch³

Step-by-step explanation:

The question is on volume of a prism and that of a cylinder

Finding the volume of the prism

V=Bh where B is the base area and h is the height

Base area=14"×14"=196 inch²

height =8"

v=196×8= 1568 in³

Finding volume of the cylinder

v= $\pi$ r²h where r is the radius of cylinder and h is the height of cylinder

r=10/2=5 inches and h=10 inches

v=3.142×5×5×10=785.5inch³

The difference in volume

Difference in volume=1568-785.5=782.5inch³

5 0

2 years ago

The equation 2x + 4k − 9 = kx − k + 1 is really a family of equations, because for each value of k, we get a different equation

Olegator [25]

You haven't shared "the given value of x," or, if you have, you haven't drawn attention to it.

Just suppose we were to choose x = 4 as a possible solution and then try to find a value of the parameter k that would make x = 4 an actual solution.

2(4) + 4k - 9 = (4)(4) - (4) + 1

Then 8 + 4k - 9 = 16 - 4 + 1, or 4k - 1 = 13. Then 4k = 14, and k = 14/4, or (after reduction) k = 7/2

If the parameter k equals 7/2, then x = 4 is a solution to the given equation.

To check this out further, start with the proposed solution x = 5 and find k.

3 0

3 years ago

What is the distance to the Earth's Horizon from point P? Enter enter the decimal in the Box round only your final answer to the

Tasya [4]

Answer:

<h2>The distance to the Eath's Horizon from point P is 352.8 mi, approximately.</h2>

Step-by-step explanation:

You observe the problem from a graphical perspective with the image attached.

Notice that side $x$ is tangent to the circle, which means is perpendicular to the radius which is equal to 3,959 mi.

We have a right triangle, that means we need to use the Pythagorean's Theorem, to find the distance to the Earth's Horizon from point P.

The hypothenuse is 3959 + 15.6 = 3974.6 mi.

$(3974.6)^{2}=x^{2} +(3959)^{2} \\x^{2} =15,797,445.16 - 15,673,681\\x=\sqrt{123,764.16} \approx 351.8$

Therefore, the distance to the Eath's Horizon from point P is 352.8 mi, approximately.

4 0

3 years ago