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Korolek [52]
3 years ago
5

RESPONDE LAS PREGUNTAS 8, 9 Y 10 DE ACUERDO CON LA

Mathematics
1 answer:
andrew-mc [135]3 years ago
6 0

Answer:  

ANSWER QUESTIONS 8, 9 AND 10 ACCORDING TO THE

NEXT INFORMATION

Luis painted a mural that

has 760 cm of

perimeter; your measurements are

show in the following

figure.

8. The expression associated with the length of the mural: 2x - 40, is

can interpret as

A. the length is 40 cm less than twice its width

B. the length exceeds the width value by 40 cm

C. the width squared, minus 40 cm, equals the length

D. 40 cm minus twice the width is the value of the length

9. What are the measurements in centimeters of the mural?

A. length: 150, width: 190 B. length: 210, width: 250

B. length: 210, width: 250

C. length: 240, width: 140 D. length: 230, width: 190

D. length: 230, width: 190

10. The area Luis used to paint the mural is

A. 2 [(2x - 40) + x] B. 2x2 - 40x

B. 2x2 - 40x

C. (2x) x - 40 D. x2 - 40x

D. x2 - 40x

Step-by-step explanation:

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You have 350 feet of fencing to enclose a rectangular plot that borders on a river. If you do not fence the side along the river
IrinaVladis [17]

The length and width that will maximize the area are 175 ft and 87.5 ft respectively

The largest area that can be enclosed is 15312.5 ft²

<h3>Area of a rectangle</h3>
  • area = lw

where

l = length

w = width

The fencing is 350 ft it is use to enclose a rectangular plot with a river occupying one part.

Therefore,

perimeter = l + 2w

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l = 350 - 2w

area = (350 - 2w)w

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average = 175/2 = 87.5

Hence, the max area is at w = 87.5 ft

Therefore,

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length = 175 ft

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