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2 years ago

Select the condition for which it is NOT possible to construct a triangle.

Mathematics

1 answer:

maw [93]2 years ago

6 0

Answer:

A triangle with side lengths 4 cm, 5 cm, and 15 cm

Step-by-step explanation:

In order to form a triangle with given side lengths, sum of any two sides must always be greater than the third side.

$4+5= 9\ngtr 15\\$

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Factor: a^2+b^2–c^2+2ab

Kruka [31]

Rearrange the polynomial:

a^2–2ab+b^2 - c^2

((a-b)(a-b))-c^2

(a-b)^2-c^2

Set x =a-b and y=c. The formula becomes

x^2-y^2

factoring this polynomial, we get

(x+y)(x-y)

Substituting back, we get:

(a+b+c)(a+b-c)

Let’s multiply it out to check:

A^2 -ab ac

- ab B^2 -bc

-ac bc -c^2

6 0

2 years ago

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A health club charges a one-time sign-up fee and a monthly membership fee. The equation y=30x+40 represents what the health club

riadik2000 [5.3K]

Answer:

$24

Step-by-step explanation:

30X + 40

$24 IS THE RATE OF CHANGE

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2 years ago

At a high school, students can choose between three art electives, four history electives, and five computer electives. Each stu

V125BC [204]

Answer:

$\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Step-by-step explanation:

Given,

Art electives = 3,

History electives = 4,

Computer electives = 5,

Total number of electives = 3 + 4 + 5 = 12,

Since, if a student chooses an art elective and a history elective,

So, the total combination of choosing an art elective and a history elective = $^3C_1\times ^4C_1$

Also, the total combination of choosing any 2 subjects out of 12 subjects = $^{12}C_2$

Hence, the probability that a student chooses an art elective and a history elective = $\frac{\text{Total combination of choosing an art elective and a history}}{\text{ Total combination of choosing any 2 subjects}}$

$=\frac{^3C_1\times ^4C_1}{^{12}C_2}$

Which is the required expression.

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2 years ago

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Need help please!!!!!!

zlopas [31]

The distance from a to c is ten units

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2 years ago

The volume of a cylinder is pi times the radius r squared multiplied by the height h. Write an expression for the volume.

Paul [167]

V= Area of the circle at the base • height =
Pi•r^2 •h

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2 years ago