Answers:
x = 5
m∠C = m∠H = 38 degrees
WORKINGS
Given that ABCD ≅ FGHJ
We know that corresponding angles of two congruent
quadrilaterals are equal
Therefore,
m∠A = m∠F
m∠B = m∠G
m∠C = m∠H
m∠D = m∠I
Given,
m∠C = 9x – 7
m∠H = 5x + 13
Since m∠C = m∠H
9x – 7 = 5x + 13
Add 7 to both sides of the equation
9x – 7 + 7 = 5x + 13 + 7
9x = 5x + 20
Subtract 5x from both sides of the equation
9x – 5x = 5x – 5x + 20
4x = 20
Divide both sides of the equation by 4
4x/4 = 20/4
x = 5
To determine the measures of angle C and angle H
m∠C = m∠H
We know that m∠C = 9x – 7
Since x = 5
m∠C = 9(5) – 7
m∠C = 45 – 7
m∠C = 38
Therefore, m∠C = m∠H = 38 degrees
For this case, the first thing we must do is define variables.
We have then:
x: number of minutes
y: final temperature
We write then the equation that models the problem:
For y = 20 we have:
Clearing x:
Answer:
The temperature of the water will be 20 degree celcius after 150 minutes
Answer:
The 1st Blank is: A pure substance, or simply a substance
The 2nd blank on the left is: Elements
The 3rd blank on the right is: Compounds
The 4th blank which is the second middle one is: A mixture
The 5th blank which is the bottom left one is: Heterogeneous mixture
The 6th blank which is the last one on the bottom right is: Homogeneous mixture
Look at the step-by-step explanation if you get confused at the bottom.
Step-by-step explanation:
The 1st Blank: I would just put a pure substance.
The 2nd blank on the left: They are three characteristics of elements but just put elements.
The 3rd blank on the right: They are three characteristics of compounds but just put compounds.
The 4th blank which is the second middle one is: The characteristics of a mixture but just put a mixture.
The 5th blank which is the bottom left one: Are the characteristics of a heterogeneous mixture but just put heterogeneous mixture.
The 6th blank which is the last one on the bottom right: Are the characteristics of a homogeneous mixture but just put homogeneous mixture.
Answer:
Step-by-step explanation:
Ones plus zero
