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3 years ago

15

Check all the equations that apply to meet the Segment Addition Postulate in segment PB. PO=7x+6, OB=3x+6 and PB=38 select all t

hat apply
7x-26=-3x
7x+6-3x-6=38
10x+12=38
10x=50
38+3x+6=7x+6
10x=26

you get 100 pts if you answer so pls help me :c

1 answer:

grandymaker [24]3 years ago

7 0

Answer:

these two apply:

10x + 12 = 38 and

10x = 26

Step-by-step explanation:

7x+6+3x+6 = 38

10x + 12 = 38

10x = 26

x = 2.6

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Draw the graph of the equation<br><br> x+y=5

Advocard [28]

well first you have to get x and y on separate sides so subtract x by both sides to put x on the right side.

now you have y = 5 - x

to graph that let's throw in some numbers for x and y and make a function table

x, y

1, 4

2, 3

3, 2

4, 1

5, 0

6, -1

and so forth

as you can see as x increases in value, y decreases in value

all you have to do now is plot those points on a graph

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3 years ago

You invest $40,000 in two funds paying 4% and 52% simple interest. The total annual interest is $2080. How much do you invest in

natali 33 [55]

9514 1404 393

Answer:

4% fund: $39,000
52% fund: $1000

Step-by-step explanation:

Let x represent the amount invested at 52%. Then (40000-x) is the amount invested at 4%. The total annual interest is ...

0.52x +0.04(40000-x) = 2080

0.48x = 480 . . . . . . . . . subtract 1600, simplify

x = 1000 . . . . . . . . . divide by 0.48

Then the amounts invested in each fund are ...

4% fund: $39,000

52% fund: $1000

6 0

3 years ago

Given the set points K+1:(-1,8),(1,0) and (2,5), find the quadratic polynomial interpolate

Sauron [17]

Answer:

The interpolating polynomial is $p(x) = 1-4x+3x^2$ .

Step-by-step explanation:

We want to find a quadratic polynomial $p(x)$ such that $p(-1)=8$ , $p(1)=0$ and $p(2)=5$ . In order to do this let us write $p(x) = a_0+a_1x+a_3x^2$ .

Now, evaluating the polynomial in the points -1, 1 and 2 we get

$\begin{cases} 8 = p(-1) &= a_0-a_1+a_2\\ 0 = p(1) &= a_0+a_1+a_2\\ 5 = p(2) &= a_0+2a_1+4a_2\end{cases}$

This relations give us a linear system of equations:

$\begin{cases} 8 &= a_0-a_1+a_2\\ 0 &= a_0+a_1+a_2\\ 5&= a_0+2a_1+4a_2\end{cases}$

where the $a_0$ , $a_1$ and $a_2$ are the unknowns.

The augmented matrix of the system is

$\begin{pmatrix}1 & -1 & 1 & 8\\ 1 & 1 & 1 & 0\\ 1 & 2 & 4 & 5\end{pmatrix}$

In this matrix it is easy to eliminate the 1's of the first column and get

$\begin{pmatrix} 1 & -1 & 1 & 8\\ 0 & 2 & 0 & -8\\ 0 & 3 & 3 & -3\end{pmatrix}$

From this matrix we can find the values of each unknown. Notice that the second row gives us $2a_2=-8$ that yields $a_1=-4$ .

Then, the third row means $3a_1+3a_2=-3$ that gives $-12+3a_2=-3$ . So, $a_2=3$ .

Finally, the first row is $a_0-a_1+a_2=8$ and substituting is $a_0+7=8$ that yields $a_0=1$ .

Therefore, the interpolating polynomial is

$p(x) = 1-4x+3x^2$ .

8 0

3 years ago

−2.8+2.4+7.8−2.8<br><br>I dont know how to solve this expression

Nataliya [291]

Step-by-step explanation:

-2.8 +2.4=-.4

-.4+7.8=7.4

7.8-2.8=5

i hope this helps ; )

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3 years ago

a skier is trying to decide whether or not to buy a season ski pass. A daily pass costs $61. A season ski pass costs $300. The s

Oksana_A [137]

D=61d+30d=91d,

S=300+30d

S<D

300+30d<91d

300<61d

d>4.91 Since days are integers,

The skier would have to go at least 5 days to make the season pass less expensive than using the daily pass.

4 0

3 years ago